如何使用 jq 将这个嵌套对象转换为扁平对象？

Question

我需要使用 jq 将此输入转换为未嵌套的对象。在 Python 中，我可以按如下方式对其进行适当的转换。

output = {(k1 + '-' + k2): v2 for k1, v1 in input.iteritems() for k2, v2 in v1.iteritems()}

但我不知道如何在 jq 中执行此操作。对嵌套对象进行操作的文档很差。

{
    "group1-permission": {
        "address": "test1",
        "others": "test2",
        "packet-capture": "test3",
        "policy": "test4",
        "schedule": "test5",
        "service": "test6"
    },
    "group2-permission": {
        "config": "none",
        "data-access": "none",
        "report-access": "none",
        "threat-weight": "none"
    },
    "group3-permission": {
        "antivirus": "none",
        "application-control": "none",
        "casi": "none",
        "data-loss-prevention": "none",
        "dnsfilter": "none",
        "icap": "none",
        "ips": "none",
        "spamfilter": "none",
        "voip": "none",
        "waf": "none",
        "webfilter": "none"
    }
}

输出应如下所示：

{
    "group1-permission-address": "test1",
    "group1-permission-others": "test2",
    "group1-permission-packet-capture": "test3",
    "group1-permission-policy": "test4",
    "group1-permission-schedule": "test5",
    "group1-permission-service": "test6",
    "group2-permission-config": "none",
    "group2-permission-data-access": "none",
    "group2-permission-report-access": "none",
    "group2-permission-threat-weight": "none",
    "group3-permission-antivirus": "none",
    "group3-permission-application-control": "none",
    "group3-permission-casi": "none",
    "group3-permission-data-loss-prevention": "none",
    "group3-permission-dnsfilter": "none",
    "group3-permission-icap": "none",
    "group3-permission-ips": "none",
    "group3-permission-spamfilter": "none",
    "group3-permission-voip": "none",
    "group3-permission-waf": "none",
    "group3-permission-webfilter": "none"
}

Answer 1

在我看来，该文档非常出色，但它有助于熟悉 map 以及对管道和过滤器的一些舒适度。不管怎样，这是一个面向地图的解决方案：

to_entries
| map( .key as $key
       | .value
       | to_entries
       | map ( { ($key + "-" + .key): .value } ) | add ) | add

这是另一个，适用于任意深度嵌套的 JSON 对象和数组：

[paths(scalars) as $path | { ($path|join("-")): getpath($path) }] | add

这里当然有一个警告：如果路径由于使用“-”作为连接字符而发生冲突，一些数据可能会丢失。

如何使用 jq 将这个嵌套对象转换为扁平对象？

How do I transform this nested object to a flattened object using jq?

json

key

object

flatten

jq