找到两个数据框的匹配并将答案重写为数据框

Question

我有两个数据框，它们被清理并合并为一个 csv 文件，数据框是这样的

  **Source                         Master**

 chang chun petrochemical      CHANG CHUN GROUP
 chang chun plastics           CHURCH AND DWIGHT CO INC
 church  dwight                CITRIX SYSTEMS ASIA PACIFIC P L
 citrix systems  pacific       CNH INDUSTRIAL N.V

现在从这些开始，我必须考虑名字并检查主名称的每个名称并找到相关的匹配项并将输出打印为另一个数据框。上面的数据帧很少，但我正在使用 20k 个值。

我的输出必须是这样的

 **Source                         Master                         Result**

 chang chun petrochemical      CHANG CHUN GROUP                 CHANG CHUN GROUP
 chang chun plastics           CHURCH AND DWIGHT CO INC         CHANG CHUN GROUP
 church  dwight                CITRIX SYSTEMS ASIA PACIFIC P L  CHURCH AND DWIGHT CO INC
 citrix systems  pacific       CNH INDUSTRIAL N.V               CITRIX SYSTEMS ASIA PACIFIC P L

我用这个 link Merging through fuzzy matching of variables in R 尝试了可能的方法，但是，到目前为止没有运气..！

提前致谢！！

当我对大量数据使用上面的代码时，结果是这样的-

使用的代码：

Mast <- pmatch(Names$I_sender_O_Receiver_Customer, Master.Names$MOD, nomatch=NA)

输出

NA NA  2  3 NA NA NA  6 NA NA  9 NA NA NA 12 NA NA NA 13 14 15 16 NA 18 19 20 21 22 NA 24 NA 26 NA 28 NA NA NA 30 NA NA 33 NA 35 36 37 NA 39 40 NA NA 43 NA 45 46 NA 48 49 50 51 52 53 54 55 56 57 58 NA
 [68] 60 61 62 NA NA NA NA 64 NA 66 67 68 69 70 71 72 73 NA 75 76 77 78 NA 79 80 81 NA 83 84 85 86 87 88

代码：

Mast <- sapply(Names$I_sender_O_Receiver_Customer, function(x) {
   agrep(x, Master.Names$MOD,value=TRUE) })

输出：

[[1]]
character(0)

[[2]]
character(0)

[[3]]
[1] " CHURCH AND DWIGHT CO INC"

[[4]]
[1] " CITRIX SYSTEMS ASIA PACIFIC P L"

[[5]]
character(0)

即使使用 for 循环也不会产生结果。

代码:

for(i in seq_len(nrow(df$ICIS_Cust_Names)))
  {
    df$reslt[i] <- grep(x = str_split(df$ICIS_Cust_Names[i]," ")[[1]][1], df$Master_Names[i],value=TRUE)
  }
  print(df$reslt)

代码 2: 仅用于 100 行的循环

for (i in 100){
  gr1$x[i] = agrep(gr1$ICIS_Cust_Names[i], gr2$Master_Names, value = TRUE, max = list(del = 0.2, ins = 0.3, sub = 0.4))
  gr2$Y[i] = agrep(gr1$ICIS_Cust_Names[i], gr2$Master_Names, value = FALSE, max = list(del = 0.2, ins = 0.3, sub = 0.4))
}

结果：

NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA

错误

Error in `$<-.data.frame`(`*tmp*`, "x", value = c(NA, NA, " church  dwight  " : 
  replacement has 3 rows, data has 100

当观察到上面的结果时，它会直接检查每个数据帧的行值，但我希望它考虑 Source 的第一个元素并检查master 的所有元素并进行匹配，同样用于休息。 如果有人可以更正我的代码，我将不胜感激！提前致谢..！

Answer 1

如果您只想检查 Master.Names 与 Names 中的第一个单词，可以这样做：

Names$Mast <- NA
for(i in seq_len(nrow(Names))) 
    Names$Mast[i] <- grep(toupper(x = strsplit(Names[i,1]," ")[[1]][1]), Master.Names$V1,value=TRUE)

编辑

使用 sapply 而不是循环可以提高您的速度：

Names$Mast <- sapply(Names$V1, function(x) {
    grep(toupper(x = strsplit(x," ")[[1]][1]), Master.Names$V1,value=TRUE)
})

结果

> Names
                        V1                            Mast
1 chang chun petrochemical                CHANG CHUN GROUP
2      chang chun plastics                CHANG CHUN GROUP
3            church dwight        CHURCH AND DWIGHT CO INC
4   citrix systems pacific CITRIX SYSTEMS ASIA PACIFIC P L

数据

Master.Names <- read.csv(text="CHANG CHUN GROUP
CHURCH AND DWIGHT CO INC
CITRIX SYSTEMS ASIA PACIFIC P L
CNH INDUSTRIAL N.V", header=FALSE)

Names <- read.csv(text="chang chun petrochemical
chang chun plastics     
church dwight          
citrix systems pacific", header=FALSE)

找到两个数据框的匹配并将答案重写为数据框

Find Match of two data frames and rewrite the answer as data frame

r

fuzzy-logic

fuzzy-comparison