Window.ShowDialog 在 return 上失败
Window.ShowDialog failes on return
我有一个自定义输入对话框,要求输入用户名和响应(因为原因)以在我的应用程序中执行特定操作。用户单击主 window 上的一个按钮,对话框就会按预期显示。
用户然后输入 his/her 名称和原因并单击确定。然后对话框关闭,但我(程序)从未收到答案。这是我的 XAML 输入对话框:
<Window x:Class="Sequence_Application_2.GUI.ForcedRackInput"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
mc:Ignorable="d"
Title="Forcera Rack" Height="300" Width="300"
WindowStartupLocation="CenterScreen">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="21*"/>
<ColumnDefinition Width="274*"/>
</Grid.ColumnDefinitions>
<TextBox Name="OperatorNameText" HorizontalAlignment="Left" Height="23" Margin="15,36,0,0" TextWrapping="Wrap" VerticalAlignment="Top" Width="120" Grid.ColumnSpan="2"/>
<Label x:Name="label" Content="Namn:" HorizontalAlignment="Left" Margin="10,10,0,0" VerticalAlignment="Top" Grid.ColumnSpan="2"/>
<Label x:Name="label1" Content="Orsak:" HorizontalAlignment="Left" Margin="10,72,0,0" VerticalAlignment="Top" Grid.ColumnSpan="2"/>
<Border BorderThickness="1" BorderBrush="Black" Grid.ColumnSpan="2" Margin="0,0,0,0.5">
<TextBox Name="ReasonText" Margin="15,98,15,0" TextWrapping="Wrap" VerticalAlignment="Top" Height="116" />
</Border>
<Button Name="OkButton" IsDefault="True" Content="OK" Click="OkButtonPressed" HorizontalAlignment="Left" Margin="26.202,233,0,0" VerticalAlignment="Top" Width="75" Cursor="Arrow" Grid.Column="1"/>
<Button Name="CancelButton" IsCancel="True" Content="Avbryt" Margin="152.202,233,47,0" VerticalAlignment="Top" Cursor="Arrow" Grid.Column="1"/>
</Grid>
</Window>
这里是 "behind code":
namespace Sequence_Application_2.GUI
{
using System.Windows;
public partial class ForcedRackInput : Window
{
public string OperatorName { get { return OperatorNameText.Text; } }
public string ForcedRackReason { get { return ReasonText.Text; } }
public ForcedRackInput()
{
InitializeComponent();
}
private void OkButtonPressed(object sender, RoutedEventArgs e)
{
this.DialogResult = true;
}
}
}
这就是我调用代码的方式(来自模型,而不是 "window class")
public void ForceClosingRack(Flow forcedFlow)
{
var forcedRackWindow = new ForcedRackInput();
string operatorName = "";
string reasonForForced = "";
if( forcedRackWindow.ShowDialog() == true)
{
operatorName = forcedRackWindow.OperatorName;
reasonForForced = forcedRackWindow.ForcedRackReason;
}
} // code jumps from "if(forcedRackWindow.... to this line when ok is clicked in the dialog
寻找解决方案已经有一段时间了,我正准备转行
感谢您的宝贵时间
我的猜测是问题不在代码中,这似乎没问题,但在您的 if
语句中。
当您 运行 您的程序处于 Debug
模式时,它应该按预期工作。
我的猜测是,您在 if
语句中分配了变量 operatorName
和 reasonForForced
,但它们没有在程序的其他任何地方使用,因此整个 if
语句被编译器忽略,并且在 运行 处于 Release
模式时不存在。
根据变量值嵌入不同行为的代码中的一个小修改可以证明我的猜测:
private void Button_Click(object sender, RoutedEventArgs e)
{
var forcedRackWindow = new ForcedWindow();
string operatorName = "foo";
string reasonForForced = "foo";
if (forcedRackWindow.ShowDialog() == true)
{
operatorName = forcedRackWindow.OperatorName;
reasonForForced = forcedRackWindow.ForcedRackReason;
}
if(!operatorName.Equals(reasonForForced))
{
MessageBox.Show("We are not the same");
}
}
我有一个自定义输入对话框,要求输入用户名和响应(因为原因)以在我的应用程序中执行特定操作。用户单击主 window 上的一个按钮,对话框就会按预期显示。
用户然后输入 his/her 名称和原因并单击确定。然后对话框关闭,但我(程序)从未收到答案。这是我的 XAML 输入对话框:
<Window x:Class="Sequence_Application_2.GUI.ForcedRackInput"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
mc:Ignorable="d"
Title="Forcera Rack" Height="300" Width="300"
WindowStartupLocation="CenterScreen">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="21*"/>
<ColumnDefinition Width="274*"/>
</Grid.ColumnDefinitions>
<TextBox Name="OperatorNameText" HorizontalAlignment="Left" Height="23" Margin="15,36,0,0" TextWrapping="Wrap" VerticalAlignment="Top" Width="120" Grid.ColumnSpan="2"/>
<Label x:Name="label" Content="Namn:" HorizontalAlignment="Left" Margin="10,10,0,0" VerticalAlignment="Top" Grid.ColumnSpan="2"/>
<Label x:Name="label1" Content="Orsak:" HorizontalAlignment="Left" Margin="10,72,0,0" VerticalAlignment="Top" Grid.ColumnSpan="2"/>
<Border BorderThickness="1" BorderBrush="Black" Grid.ColumnSpan="2" Margin="0,0,0,0.5">
<TextBox Name="ReasonText" Margin="15,98,15,0" TextWrapping="Wrap" VerticalAlignment="Top" Height="116" />
</Border>
<Button Name="OkButton" IsDefault="True" Content="OK" Click="OkButtonPressed" HorizontalAlignment="Left" Margin="26.202,233,0,0" VerticalAlignment="Top" Width="75" Cursor="Arrow" Grid.Column="1"/>
<Button Name="CancelButton" IsCancel="True" Content="Avbryt" Margin="152.202,233,47,0" VerticalAlignment="Top" Cursor="Arrow" Grid.Column="1"/>
</Grid>
</Window>
这里是 "behind code":
namespace Sequence_Application_2.GUI
{
using System.Windows;
public partial class ForcedRackInput : Window
{
public string OperatorName { get { return OperatorNameText.Text; } }
public string ForcedRackReason { get { return ReasonText.Text; } }
public ForcedRackInput()
{
InitializeComponent();
}
private void OkButtonPressed(object sender, RoutedEventArgs e)
{
this.DialogResult = true;
}
}
}
这就是我调用代码的方式(来自模型,而不是 "window class")
public void ForceClosingRack(Flow forcedFlow)
{
var forcedRackWindow = new ForcedRackInput();
string operatorName = "";
string reasonForForced = "";
if( forcedRackWindow.ShowDialog() == true)
{
operatorName = forcedRackWindow.OperatorName;
reasonForForced = forcedRackWindow.ForcedRackReason;
}
} // code jumps from "if(forcedRackWindow.... to this line when ok is clicked in the dialog
寻找解决方案已经有一段时间了,我正准备转行
感谢您的宝贵时间
我的猜测是问题不在代码中,这似乎没问题,但在您的 if
语句中。
当您 运行 您的程序处于 Debug
模式时,它应该按预期工作。
我的猜测是,您在 if
语句中分配了变量 operatorName
和 reasonForForced
,但它们没有在程序的其他任何地方使用,因此整个 if
语句被编译器忽略,并且在 运行 处于 Release
模式时不存在。
根据变量值嵌入不同行为的代码中的一个小修改可以证明我的猜测:
private void Button_Click(object sender, RoutedEventArgs e)
{
var forcedRackWindow = new ForcedWindow();
string operatorName = "foo";
string reasonForForced = "foo";
if (forcedRackWindow.ShowDialog() == true)
{
operatorName = forcedRackWindow.OperatorName;
reasonForForced = forcedRackWindow.ForcedRackReason;
}
if(!operatorName.Equals(reasonForForced))
{
MessageBox.Show("We are not the same");
}
}