如何连续计算文本文件的结果

Question

我想知道如何计算文本文件中的连续结果。我写了这段代码：

from itertools import groupby

def count_runs_of(seq, val):
    return sum(key == val for key, group in groupby(seq))

示例：

>>> count_runs_of([1, 2, 3, 3, 3, 1, 2, 2, 4], 3)
1
>>> count_runs_of([1, 2, 3, 3, 3, 1, 2, 2, 4, 3, 3], 3)
2
>>> count_runs_of([1, 2, 3, 3, 3, 1, 2, 2, 4, 3, 3, 9, 2, 4, 3, 3, 3], 3)
3
>>> count_runs_of([1, 2, 3, 3, 3, 1, 2, 2, 4], 2)
2

我想知道意甲有多长。例如，当我在第一个结果中有“1”时，我还想打印“3”（因为连续有 3 x 3）。你可以帮帮我吗？谢谢

Answer 1

def count_runs_of(seq, val):
    return [len(list(group)) for key, group in groupby(seq) if key == val]

示例

>>> count_runs_of([1, 2, 3, 3, 3, 1, 2, 2, 4, 3, 3], 3)
[3, 2]

Answer 2

你已经非常接近了，你可以通过使用 sum() 和生成器表达式对其进行循环来获得组的长度。这将 return 列表中所有此类运行的长度：

>>> def count_runs_of(seq, val):
    return [sum(1 for _ in g) for k, g in groupby(seq) if k == val]
... 
>>> count_runs_of([1, 2, 3, 3, 3, 1, 2, 2, 4], 3)
[3]
>>> count_runs_of([1, 2, 3, 3, 3, 1, 2, 2, 4, 3, 3], 3)
[3, 2]

如何连续计算文本文件的结果

How to count in a row results from text file

python

python-3.x