MySQL said 1064 你的 SQL 语法有误

Question

我为我的用户注册页面写了一个 MYSQL 过程，我已经写了 PHP 部分从那里发送数据到 MySQL，它工作正常（试过虚拟数据和检索）。但是我猜我的处理程序或交易存在某种问题

这是我的程序：

BEGIN
DECLARE unamec INT;
DECLARE emailc INT;
DECLARE m INT;
DECLARE msg VARCHAR(100);
DECLARE EXIT HANDLER FOR SQLEXCEPTION SET m=1;
    START TRANSACTION;
    SET autocommit=0;
    SELECT COUNT(*) INTO unamec FROM login WHERE uname=`@user`;
    IF unamec=0 THEN
        SELECT COUNT(*) INTO emailc FROM login WHERE email=@email;
        IF emailc=0 THEN
            INSERT INTO login (uname, hash, email, role) values(@user,MD5(@password),@email,'1');
            SET msg='Successfully Registered';
        ELSE
            SET msg='Email Already Exists';
        END IF;
    ELSE
        SET msg='Username Already Exists';
    END IF;
COMMIT;
END;
END;
IF m=1 THEN
ROLLBACK;
SET msg='ERROR';
END IF;
SELECT msg as message;
END

我总是得到错误

MySQL said: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near
'END;
IF m=1 THEN
ROLLBACK;
SET msg='ERROR';
END IF;
SELECT msg as message;' at line 23

有什么明显的我遗漏的吗？我已经尝试了一段时间来解决这个问题，几乎所有结果都显示相同的错误。

任何帮助将不胜感激。

Answer 1

好的，我编辑了自己的代码并得到了所需的结果。

我所做的更改是：

BEGIN
DECLARE unamec INT;
DECLARE emailc INT;
DECLARE m INT;
DECLARE msg VARCHAR(100);
DECLARE EXIT HANDLER FOR SQLEXCEPTION
START TRANSACTION;
SET autocommit=0;
SELECT COUNT(*) INTO unamec FROM login WHERE uname=`@user`;
IF unamec=0 THEN
    SELECT COUNT(*) INTO emailc FROM login WHERE email=@email;
    IF emailc=0 THEN
        INSERT INTO login (uname, hash, email, role) values(@user,MD5(@password),@email,'1');
        SET msg='Successfully Registered';
    ELSE
        SET msg='Email Already Exists';
    END IF;
ELSE
    SET msg='Username Already Exists';
END IF;
COMMIT;
BEGIN
ROLLBACK;
SET msg='ERROR';
END;
SELECT msg as message;
END

如果有人得到任何其他答案，仍然不胜感激。

无论如何，上面的代码现在可以正常工作了。

MySQL said 1064 你的 SQL 语法有误

MySQL said 1064 You have an error in your SQL syntax

mysql

sql

mysql-error-1064