如何使用 java 在 openCv 中找到矩形的角
how to find the corner of rectangle in openCv with java
我写了这段检测矩形的代码,但我写不出检测角的代码。
public class RectDetection {
public static void main(String[] args) {
System.loadLibrary(Core.NATIVE_LIBRARY_NAME);
Mat rectengle=Imgcodecs.imread("D:\sepano\rect.png");
Mat img =new Mat();
img=rectengle.clone();
Imgproc.cvtColor(rectengle, img, Imgproc.COLOR_BGR2GRAY);
Imgproc.GaussianBlur(img, img, new org.opencv.core.Size(1, 1), 2, 2);
Imgproc.Canny(img,img,3, 3,5,false);
List<MatOfPoint> contours = new ArrayList<MatOfPoint>();
Imgproc.findContours(img, contours, new Mat(), Imgproc.RETR_LIST, Imgproc.CHAIN_APPROX_SIMPLE);
MatOfPoint temp_contour = contours.get(0); //the largest is at the index 0 for starting point
for (int idx = 0; idx < contours.size(); idx++) {
temp_contour = contours.get(idx);
MatOfPoint2f new_mat = new MatOfPoint2f( temp_contour.toArray() );
int contourSize = (int)temp_contour.total();
MatOfPoint2f approxCurve_temp = new MatOfPoint2f();
Imgproc.approxPolyDP(new_mat, approxCurve_temp, contourSize*0.05, true);
if (approxCurve_temp.total()==8) {
MatOfPoint points = new MatOfPoint( approxCurve_temp.toArray() );
Rect rect = Imgproc.boundingRect(points);
Imgproc.rectangle(img, new Point(rect.x,rect.y), new Point(rect.x+rect.width,rect.y+rect.height), new Scalar(170,0,150,0), 5);}}
这是一个 python 角点检测代码,但我无法将其转换为 java:
import numpy as np
import cv2
from matplotlib import pyplot as plt
img = cv2.imread('simple.jpg')
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
corners = cv2.goodFeaturesToTrack(gray,25,0.01,10)
corners = np.int0(corners)
for i in corners:
x,y = i.ravel()
cv2.circle(img,(x,y),3,255,-1)
plt.imshow(img),plt.show()
有什么可以帮助我的吗????
仔细查看您的 java 代码...
这一行:
Imgproc.rectangle(img, new Point(rect.x,rect.y), new Point(rect.x+rect.width,rect.y+rect.height), new Scalar(170,0,150,0), 5);
Point(rect.x,rect.y)
对应矩形的左上角,Point(rect.x+rect.width,rect.y+rect.height)
对应矩形的右下角。
矩形检测代码应该足够了,4个角如下:
Point(rect.x,rect.y)
//Top Left
Point(rect.x+rect.width,rect.y)
//Top Right
Point(rect.x,rect.y+rect.height)
//Bottom Left
Point(rect.x+rect.width,rect.y+rect.height)
//Bottom Right
我写了这段检测矩形的代码,但我写不出检测角的代码。
public class RectDetection {
public static void main(String[] args) {
System.loadLibrary(Core.NATIVE_LIBRARY_NAME);
Mat rectengle=Imgcodecs.imread("D:\sepano\rect.png");
Mat img =new Mat();
img=rectengle.clone();
Imgproc.cvtColor(rectengle, img, Imgproc.COLOR_BGR2GRAY);
Imgproc.GaussianBlur(img, img, new org.opencv.core.Size(1, 1), 2, 2);
Imgproc.Canny(img,img,3, 3,5,false);
List<MatOfPoint> contours = new ArrayList<MatOfPoint>();
Imgproc.findContours(img, contours, new Mat(), Imgproc.RETR_LIST, Imgproc.CHAIN_APPROX_SIMPLE);
MatOfPoint temp_contour = contours.get(0); //the largest is at the index 0 for starting point
for (int idx = 0; idx < contours.size(); idx++) {
temp_contour = contours.get(idx);
MatOfPoint2f new_mat = new MatOfPoint2f( temp_contour.toArray() );
int contourSize = (int)temp_contour.total();
MatOfPoint2f approxCurve_temp = new MatOfPoint2f();
Imgproc.approxPolyDP(new_mat, approxCurve_temp, contourSize*0.05, true);
if (approxCurve_temp.total()==8) {
MatOfPoint points = new MatOfPoint( approxCurve_temp.toArray() );
Rect rect = Imgproc.boundingRect(points);
Imgproc.rectangle(img, new Point(rect.x,rect.y), new Point(rect.x+rect.width,rect.y+rect.height), new Scalar(170,0,150,0), 5);}}
这是一个 python 角点检测代码,但我无法将其转换为 java:
import numpy as np
import cv2
from matplotlib import pyplot as plt
img = cv2.imread('simple.jpg')
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
corners = cv2.goodFeaturesToTrack(gray,25,0.01,10)
corners = np.int0(corners)
for i in corners:
x,y = i.ravel()
cv2.circle(img,(x,y),3,255,-1)
plt.imshow(img),plt.show()
有什么可以帮助我的吗????
仔细查看您的 java 代码...
这一行:
Imgproc.rectangle(img, new Point(rect.x,rect.y), new Point(rect.x+rect.width,rect.y+rect.height), new Scalar(170,0,150,0), 5);
Point(rect.x,rect.y)
对应矩形的左上角,Point(rect.x+rect.width,rect.y+rect.height)
对应矩形的右下角。
矩形检测代码应该足够了,4个角如下:
Point(rect.x,rect.y)
//Top Left
Point(rect.x+rect.width,rect.y)
//Top Right
Point(rect.x,rect.y+rect.height)
//Bottom Left
Point(rect.x+rect.width,rect.y+rect.height)
//Bottom Right