访问 sqlalchemy 关联对象中的额外数据

Question

User 对象可以通过许多不同的方式与 Project 相关，由 Job 关联 table 指定。在我的模板文件中，我试图遍历 current_user.projects 中的所有项目，并在每个项目中为该项目中的该用户指定 Job 是什么......但我不能语法正确。

型号

class Project(db.Model):
    id = db.Column(db.Integer(), primary_key=True)
    title = db.Column(db.String(80))
    users = db.relationship("Job", back_populates="project")

class User(db.Model, UserMixin):
    id = db.Column(db.Integer, primary_key=True)
    first_name = db.Column(db.String(155))
    last_name = db.Column(db.String(155))
    email = db.Column(db.String(255), unique=True)
    password = db.Column(db.String(255))
    projects = db.relationship("Job", back_populates="user")

# defines a user's role related to each assigned project
class Job(db.Model):
    __tablename__ = 'job'
    user_id = db.Column(db.Integer, db.ForeignKey('user.id'), primary_key=True)
    project_id = db.Column(db.Integer, db.ForeignKey('project.id'), primary_key=True)
    job = db.Column(db.String(50))
    user = db.relationship("User", back_populates="projects")
    project = db.relationship("Project", back_populates="users")

    def __init__(self, user_id, project_id, job="client"):
        self.user_id = user_id
        self.project_id = project_id
        self.job = job

VIEW

@app.route('/projects')
@login_required
def projects():
    projects = Project.query.join(Job).filter_by(user_id=current_user.id).all() 
    # current_user.projects would probably do the same thing            
    return render_template('project/projects.html', projects=projects)

模板

<div class="accordion style-two gradient-bg">
    <div class="panel-group" id="accordion-2">
        {% for project in projects %}
        <div class="panel panel-default">
            <!-- Accordian Title -->
            <div class="panel-heading">
                <div class="panel-title">
                    <a class="accordion-toggle collapsed" href="#{{ project.id }}" data-parent="#accordion-2" data-toggle="collapse" aria-expanded="false">
                        {{ project }} - HELP NEEDED HERE--> ({{ project.user[0].job }})
                    </a>
                </div>
            </div>
            <!-- Accordian Detail -->
            <div id="{{ project.id }}" class="panel-collapse collapse">
                <div class="panel-body">
                    <div class="container">
                        <div class="row">
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                        <p>Prima tritani veritus id pro, elitr hendrerit comprehensam ei per. Doming integre aliquando has at. Ea eam aeterno lobortis, ea est mutat laudem semper. Pertinax urbanitas nec ne, quo aliquip voluptaria scriptorem ut. Ut mel tractatos reprimique contentiones, adhuc nulla apeirian usu no, mel imperdiet molestiae abhorreant ut.</p> 
                        </div>
                    </div>
                </div>
            </div>
        </div>
        {% endfor %}
   </div>
</div>

如上图所示，我有 project.users[0].job 这将显示正确的信息，因为我在系统中只有一个用户。我如何在模板级别指定我正在寻找与 current_user 相关联的工作，因为我正在遍历 projects？谢谢！

Answer 1

正如评论中所建议的，最简单的方法是简单地查询关联的 table 开头：projects = Job.query.filter_by(user_id=current_user.id).all()

我已经准备好访问每个 Project 引用的 (project.project) 并且还可以获得作业的详细信息 (project.job)。

访问 sqlalchemy 关联对象中的额外数据

Accessing extra data in a sqlalchemy associated object

python

flask

sqlalchemy

flask-sqlalchemy

associated-object