Snakeyaml 似乎不必要地将简单值包装在列表中
Snakeyaml appears to unnecessarily wrap simple values in lists
我正在尝试使用 Groovy 和 Snakeyaml 解析以下 YAML 文件(显然我已经清理了数据,但这足以证明问题):
---
info:
summary: Snakeyaml Issue
examples:
- 1st example:
name: Example 1
sublist:
- 0.1:
foo: bar
我希望得到以下陈述:
println resource.info.summary
println resource.examples."1st example".name
println resource.examples."1st example".sublist."0.1"
产量:
Snakeyaml Issue
Example 1
[foo:bar]
和:
println resource.examples."1st example".sublist."0.1".foo
产量:
bar
然而,实际输出来自:
println resource.info.summary
println resource.examples."1st example".name
println resource.examples."1st example".sublist."0.1"
println resource.examples."1st example".sublist."0.1".foo
是:
Snakeyaml Issue
[Example 1]
[[[foo:bar]]]
[[bar]]
我只能通过包含列表索引来获得所需的输出:
println resource.info.summary
println resource.examples[0]."1st example".name
println resource.examples[0]."1st example".sublist[0]."0.1"
println resource.examples[0]."1st example".sublist[0]."0.1".foo
这似乎是不必要的。也许我误解了数据的结构?
为了完整起见,我用来说明问题的 groovy 代码如下所示(我从网上抓取了 CustomerResolver 代码,以便将浮点数保留为字符串):
import org.yaml.snakeyaml.DumperOptions
import org.yaml.snakeyaml.Yaml
import org.yaml.snakeyaml.constructor.Constructor
import org.yaml.snakeyaml.nodes.Tag
import org.yaml.snakeyaml.representer.Representer
import org.yaml.snakeyaml.resolver.Resolver
def fileName = "example.yaml"
def Yaml yaml = new Yaml(new Constructor(), new Representer(), new DumperOptions(),
new CustomResolver())
def resource = yaml.load(new File(fileName).newInputStream())
println resource.info.summary
println resource.examples."1st example".name
println resource.examples."1st example".sublist."0.1"
println resource.examples."1st example".sublist."0.1".foo
class CustomResolver extends Resolver {
/*
* Do not resolve float and timestamp
*/
protected void addImplicitResolvers() {
addImplicitResolver(Tag.BOOL, BOOL, "yYnNtTfFoO");
addImplicitResolver(Tag.INT, INT, "-+0123456789");
addImplicitResolver(Tag.MERGE, MERGE, "<");
addImplicitResolver(Tag.NULL, NULL, "~nN[=18=]");
addImplicitResolver(Tag.NULL, EMPTY, null);
}
}
有什么想法吗?
您访问 yaml 的方式存在问题
examples
首先包含 list
然后才包含 object
键 1st example
对于你的情况试试这个访问:
println resource.info.summary
println resource.examples[0]."1st example"
println resource.examples[0]."1st example".name
println resource.examples[0]."1st example".sublist[0]
println resource.examples[0]."1st example".sublist[0]."0.1"
println resource.examples[0]."1st example".sublist[0]."0.1".foo
要了解列表访问器的工作原理,请查看此示例:
@Grab(group='org.yaml', module='snakeyaml', version='1.18')
import org.yaml.snakeyaml.Yaml
def Yaml yaml = new Yaml()
def resource = yaml.load(new StringReader('''---
info:
summary: Snakeyaml Issue
examples:
- 1st example:
name: Example 1
- 1st example:
name: Example 2
- 1st example:
xname: Example 3
- 2nd example:
name: Example 4
'''))
println resource.examples."1st example"
//prints> [[name:Example 1], [name:Example 2], [xname:Example 3], null]
println resource.examples."1st example".name
//prints> [Example 1, Example 2, null]
我正在尝试使用 Groovy 和 Snakeyaml 解析以下 YAML 文件(显然我已经清理了数据,但这足以证明问题):
---
info:
summary: Snakeyaml Issue
examples:
- 1st example:
name: Example 1
sublist:
- 0.1:
foo: bar
我希望得到以下陈述:
println resource.info.summary
println resource.examples."1st example".name
println resource.examples."1st example".sublist."0.1"
产量:
Snakeyaml Issue
Example 1
[foo:bar]
和:
println resource.examples."1st example".sublist."0.1".foo
产量:
bar
然而,实际输出来自:
println resource.info.summary
println resource.examples."1st example".name
println resource.examples."1st example".sublist."0.1"
println resource.examples."1st example".sublist."0.1".foo
是:
Snakeyaml Issue
[Example 1]
[[[foo:bar]]]
[[bar]]
我只能通过包含列表索引来获得所需的输出:
println resource.info.summary
println resource.examples[0]."1st example".name
println resource.examples[0]."1st example".sublist[0]."0.1"
println resource.examples[0]."1st example".sublist[0]."0.1".foo
这似乎是不必要的。也许我误解了数据的结构?
为了完整起见,我用来说明问题的 groovy 代码如下所示(我从网上抓取了 CustomerResolver 代码,以便将浮点数保留为字符串):
import org.yaml.snakeyaml.DumperOptions
import org.yaml.snakeyaml.Yaml
import org.yaml.snakeyaml.constructor.Constructor
import org.yaml.snakeyaml.nodes.Tag
import org.yaml.snakeyaml.representer.Representer
import org.yaml.snakeyaml.resolver.Resolver
def fileName = "example.yaml"
def Yaml yaml = new Yaml(new Constructor(), new Representer(), new DumperOptions(),
new CustomResolver())
def resource = yaml.load(new File(fileName).newInputStream())
println resource.info.summary
println resource.examples."1st example".name
println resource.examples."1st example".sublist."0.1"
println resource.examples."1st example".sublist."0.1".foo
class CustomResolver extends Resolver {
/*
* Do not resolve float and timestamp
*/
protected void addImplicitResolvers() {
addImplicitResolver(Tag.BOOL, BOOL, "yYnNtTfFoO");
addImplicitResolver(Tag.INT, INT, "-+0123456789");
addImplicitResolver(Tag.MERGE, MERGE, "<");
addImplicitResolver(Tag.NULL, NULL, "~nN[=18=]");
addImplicitResolver(Tag.NULL, EMPTY, null);
}
}
有什么想法吗?
您访问 yaml 的方式存在问题
examples
首先包含 list
然后才包含 object
键 1st example
对于你的情况试试这个访问:
println resource.info.summary
println resource.examples[0]."1st example"
println resource.examples[0]."1st example".name
println resource.examples[0]."1st example".sublist[0]
println resource.examples[0]."1st example".sublist[0]."0.1"
println resource.examples[0]."1st example".sublist[0]."0.1".foo
要了解列表访问器的工作原理,请查看此示例:
@Grab(group='org.yaml', module='snakeyaml', version='1.18')
import org.yaml.snakeyaml.Yaml
def Yaml yaml = new Yaml()
def resource = yaml.load(new StringReader('''---
info:
summary: Snakeyaml Issue
examples:
- 1st example:
name: Example 1
- 1st example:
name: Example 2
- 1st example:
xname: Example 3
- 2nd example:
name: Example 4
'''))
println resource.examples."1st example"
//prints> [[name:Example 1], [name:Example 2], [xname:Example 3], null]
println resource.examples."1st example".name
//prints> [Example 1, Example 2, null]