在一个连接中查找最大值和计数
Finding max and count in one join
这个问题可能有一个简单的解决方案,但不幸的是,我想不通。
我有两个 table:Table A 和 Table B
Table A Table B
------------------- ------------------------------
Id NoOfItems Id itemNo deliveredDate
X1 3 X1 1 2017-07-01
X1 2 2017-07-02
X1 3 2017-07-03
所以我需要的是将每个 Id 的最大交付日期添加到 table A,但前提是 Table B 中的交付项目数等于 Table A 中的 NoOfItems .
到目前为止我已经写了这个查询:
SELECT *
FROM A
OUTER APPLY
(
SELECT TOP 1 *
FROM B
WHERE A.Id =B.Id
ORDER BY
B.DeliveredDate DESC
) s
where A.NoOfItems= (select count(1) from B )
)
你几乎成功了:
;with A as
(select 1 ID, 3 NoOfItems
union all select 2 ID, 2 NoOfItems
union all select 3 ID, 1 NoOfItems
)
, B as
(select 1 id, 1 itemno, '2017-07-01' deliveredDate
union all select 1, 2, '2017-07-02'
union all select 1, 3, '2017-07-03'
union all select 2, 1, '2017-08-02'
union all select 2, 2, '2017-08-03'
)
SELECT *
FROM A
OUTER APPLY
(
SELECT TOP 1 *
FROM B
WHERE A.Id =B.Id
ORDER BY
B.DeliveredDate DESC
) s
where A.NoOfItems = (select count(1) from B WHERE B.id = A.ID)
我只想用一个简单的 join
和 group by
:
select a.*,
(case when b.cnt = a.noofitems then b.deliveredDate end)
from a join
(select b.id, count(*) as cnt, max(deliveredDate) as deliveredDate
from b
group by b.id
) b;
on a.id = b.id;
不清楚您是否要将交付日期分配给所有行,并为匹配的行分配 NULL
值(如上述查询)。或者,如果您想过滤掉不匹配的行(在这种情况下使用 where
)。
这个问题可能有一个简单的解决方案,但不幸的是,我想不通。
我有两个 table:Table A 和 Table B
Table A Table B
------------------- ------------------------------
Id NoOfItems Id itemNo deliveredDate
X1 3 X1 1 2017-07-01
X1 2 2017-07-02
X1 3 2017-07-03
所以我需要的是将每个 Id 的最大交付日期添加到 table A,但前提是 Table B 中的交付项目数等于 Table A 中的 NoOfItems .
到目前为止我已经写了这个查询:
SELECT *
FROM A
OUTER APPLY
(
SELECT TOP 1 *
FROM B
WHERE A.Id =B.Id
ORDER BY
B.DeliveredDate DESC
) s
where A.NoOfItems= (select count(1) from B )
)
你几乎成功了:
;with A as
(select 1 ID, 3 NoOfItems
union all select 2 ID, 2 NoOfItems
union all select 3 ID, 1 NoOfItems
)
, B as
(select 1 id, 1 itemno, '2017-07-01' deliveredDate
union all select 1, 2, '2017-07-02'
union all select 1, 3, '2017-07-03'
union all select 2, 1, '2017-08-02'
union all select 2, 2, '2017-08-03'
)
SELECT *
FROM A
OUTER APPLY
(
SELECT TOP 1 *
FROM B
WHERE A.Id =B.Id
ORDER BY
B.DeliveredDate DESC
) s
where A.NoOfItems = (select count(1) from B WHERE B.id = A.ID)
我只想用一个简单的 join
和 group by
:
select a.*,
(case when b.cnt = a.noofitems then b.deliveredDate end)
from a join
(select b.id, count(*) as cnt, max(deliveredDate) as deliveredDate
from b
group by b.id
) b;
on a.id = b.id;
不清楚您是否要将交付日期分配给所有行,并为匹配的行分配 NULL
值(如上述查询)。或者,如果您想过滤掉不匹配的行(在这种情况下使用 where
)。