如何draw/Form用两点画圆?
How to draw/Form circle with two points?
我要画一个圆,我只有两个points.Now我需要找到圆心和半径?您可以顺时针方向围成圆圈。
提前致谢
不,那是不可能的。
在中心点 A + B 处创建两个半径相同的圆。在这两个圆的交点处创建一个半径相同的圆....
然后用另一个半径做同样的事情....
这是解决问题的蛮力方法。
编辑
如果两点之间的线几乎沿 x 直线(意味着半径将接近 Infinity
),则添加最大迭代限制以切断计算
还有动画,因为这让一切变得更好:)
var canvas = document.body.appendChild(document.createElement("canvas"));
var ctx = canvas.getContext("2d");
canvas.width = 1000;
canvas.height = 1000;
var points = [
{ x: parseInt(prompt("x1", "110")), y: parseInt(prompt("y1", "120")), r: 5 },
{ x: parseInt(prompt("x2", "110")), y: parseInt(prompt("y2", "60")), r: 5 },
];
function calculateRemainingPoint(points, x, precision, maxIteration) {
if (x === void 0) { x = 0; }
if (precision === void 0) { precision = 0.001; }
if (maxIteration === void 0) { maxIteration = 100000; }
var newPoint = {
x: x,
y: (points[0].y + points[1].y) / 2,
r: 50
};
var d0 = distance(points[0].x, points[0].y, x, newPoint.y);
var d1 = distance(points[1].x, points[1].y, x, newPoint.y);
var iteration = 0;
//Bruteforce approach
while (Math.abs(d0 - d1) > precision && iteration < maxIteration) {
var oldDiff = Math.abs(d0 - d1);
var oldY = newPoint.y;
iteration++;
newPoint.y += oldDiff / 10;
d0 = distance(points[0].x, points[0].y, x, newPoint.y);
d1 = distance(points[1].x, points[1].y, x, newPoint.y);
var diff_1 = Math.abs(d0 - d1);
if (diff_1 > oldDiff) {
newPoint.y = oldY - oldDiff / 10;
d0 = distance(points[0].x, points[0].y, x, newPoint.y);
d1 = distance(points[1].x, points[1].y, x, newPoint.y);
}
}
var diff = (points[0].x + points[1].x) / points[0].x;
newPoint.r = d0;
return newPoint;
}
points.push(calculateRemainingPoint(points));
function distance(x1, y1, x2, y2) {
var a = x1 - x2;
var b = y1 - y2;
return Math.sqrt(a * a + b * b);
}
function draw() {
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.beginPath();
ctx.moveTo(-canvas.width, canvas.height / 2);
ctx.lineTo(canvas.width, canvas.height / 2);
ctx.stroke();
ctx.closePath();
ctx.beginPath();
ctx.moveTo(canvas.width / 2, -canvas.height);
ctx.lineTo(canvas.width / 2, canvas.height);
ctx.stroke();
ctx.closePath();
for (var pointIndex = 0; pointIndex < points.length; pointIndex++) {
var point = points[pointIndex];
ctx.beginPath();
ctx.arc(point.x + canvas.width / 2, canvas.height / 2 - point.y, point.r, 0, Math.PI * 2);
ctx.arc(point.x + canvas.width / 2, canvas.height / 2 - point.y, 2, 0, Math.PI * 2);
ctx.stroke();
ctx.closePath();
}
}
setInterval(function () {
points = points.slice(0, 2);
points[Math.floor(Math.random() * points.length) % points.length][Math.random() > 0.5 ? 'x' : 'y'] = Math.random() * canvas.width - canvas.width / 2;
setTimeout(function () {
points.push(calculateRemainingPoint(points));
requestAnimationFrame(draw);
}, 1000 / 60);
}, 1000);
draw();
我要画一个圆,我只有两个points.Now我需要找到圆心和半径?您可以顺时针方向围成圆圈。
提前致谢
不,那是不可能的。
在中心点 A + B 处创建两个半径相同的圆。在这两个圆的交点处创建一个半径相同的圆....
然后用另一个半径做同样的事情....
这是解决问题的蛮力方法。
编辑
如果两点之间的线几乎沿 x 直线(意味着半径将接近 Infinity
),则添加最大迭代限制以切断计算
还有动画,因为这让一切变得更好:)
var canvas = document.body.appendChild(document.createElement("canvas"));
var ctx = canvas.getContext("2d");
canvas.width = 1000;
canvas.height = 1000;
var points = [
{ x: parseInt(prompt("x1", "110")), y: parseInt(prompt("y1", "120")), r: 5 },
{ x: parseInt(prompt("x2", "110")), y: parseInt(prompt("y2", "60")), r: 5 },
];
function calculateRemainingPoint(points, x, precision, maxIteration) {
if (x === void 0) { x = 0; }
if (precision === void 0) { precision = 0.001; }
if (maxIteration === void 0) { maxIteration = 100000; }
var newPoint = {
x: x,
y: (points[0].y + points[1].y) / 2,
r: 50
};
var d0 = distance(points[0].x, points[0].y, x, newPoint.y);
var d1 = distance(points[1].x, points[1].y, x, newPoint.y);
var iteration = 0;
//Bruteforce approach
while (Math.abs(d0 - d1) > precision && iteration < maxIteration) {
var oldDiff = Math.abs(d0 - d1);
var oldY = newPoint.y;
iteration++;
newPoint.y += oldDiff / 10;
d0 = distance(points[0].x, points[0].y, x, newPoint.y);
d1 = distance(points[1].x, points[1].y, x, newPoint.y);
var diff_1 = Math.abs(d0 - d1);
if (diff_1 > oldDiff) {
newPoint.y = oldY - oldDiff / 10;
d0 = distance(points[0].x, points[0].y, x, newPoint.y);
d1 = distance(points[1].x, points[1].y, x, newPoint.y);
}
}
var diff = (points[0].x + points[1].x) / points[0].x;
newPoint.r = d0;
return newPoint;
}
points.push(calculateRemainingPoint(points));
function distance(x1, y1, x2, y2) {
var a = x1 - x2;
var b = y1 - y2;
return Math.sqrt(a * a + b * b);
}
function draw() {
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.beginPath();
ctx.moveTo(-canvas.width, canvas.height / 2);
ctx.lineTo(canvas.width, canvas.height / 2);
ctx.stroke();
ctx.closePath();
ctx.beginPath();
ctx.moveTo(canvas.width / 2, -canvas.height);
ctx.lineTo(canvas.width / 2, canvas.height);
ctx.stroke();
ctx.closePath();
for (var pointIndex = 0; pointIndex < points.length; pointIndex++) {
var point = points[pointIndex];
ctx.beginPath();
ctx.arc(point.x + canvas.width / 2, canvas.height / 2 - point.y, point.r, 0, Math.PI * 2);
ctx.arc(point.x + canvas.width / 2, canvas.height / 2 - point.y, 2, 0, Math.PI * 2);
ctx.stroke();
ctx.closePath();
}
}
setInterval(function () {
points = points.slice(0, 2);
points[Math.floor(Math.random() * points.length) % points.length][Math.random() > 0.5 ? 'x' : 'y'] = Math.random() * canvas.width - canvas.width / 2;
setTimeout(function () {
points.push(calculateRemainingPoint(points));
requestAnimationFrame(draw);
}, 1000 / 60);
}, 1000);
draw();