如何使用 HtmlUnit 以表单形式提交文件

Question

我对这个表格有疑问

<form action="/incoming/Upload.cfg" enctype="multipart/form-data" method="post" onsubmit="return doSubmit();">
  <table id="autoWidth" border="0" style="width: 100%;">
    <tbody>
      <tr>
        <td class="h1" colspan="4" id="t_title">
          Резервная копия и Восстановление
        </td>
      </tr>
      <tr>
        <td class="blue" colspan="4"/>
      </tr>
      <tr>
        <td class="Item" id="t_backup">
          Сохранить:
        </td>
        <td colspan="3">
          <input type="button" class="buttonBigL" name="Backup" value="Резервная копия" onclick="location.href='config.bin';"/>
        </td>
      </tr>
      <tr>
        <td class="Item" id="t_file">
          Файл:
        </td>
        <td>
          <input class="text" name="filename" type="file" size="20" onkeydown="return false"/>

            
        </td>
        <td>
          <input name="Restore" type="submit" class="buttonBigL" id="Submit" value="Восстановить"/>
        </td>
        <td width="100%">
           
        </td>
      </tr>
      <tr>
        <td class="blue" colspan="4"/>
      </tr>
    </tbody>
  </table>
</form>

我想插入 "Backup" 文件并提交表单（在浏览器中单击 "Restore button"）。代码。

private String model = "src/test/resources/config.bin";
final WebClient webClient = new WebClient(BrowserVersion.CHROME);
        webClient.getOptions().setTimeout(20000);
        webClient.getOptions().setJavaScriptEnabled(true);
        webClient.getOptions().setThrowExceptionOnScriptError(false);
        webClient.getOptions().setThrowExceptionOnFailingStatusCode(false);
  webClient.setConfirmHandler(new ConfirmHandler() {
            public boolean handleConfirm(Page page, String message) {
                System.out.println("!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1123");
                return true;
            }
        });
 final HtmlPage frame = ((HtmlPage) page.getFrameByName("frame").getEnclosedPage());

        List<HtmlForm> forms = mainFrame.getForms();

        HtmlForm htmlForm = forms.get(0);

        htmlForm.<HtmlFileInput>getInputByName("filename").setValueAttribute(model);
        htmlForm.<HtmlFileInput>getInputByName("filename").setContentType("multipart/form-data");
        HtmlPage page = (HtmlPage) mainFrame.executeJavaScript("return doSubmit()").getNewPage();

当我执行 JS 时出现错误

StrictErrorReporter: error: message=[invalid return] sourceName=[injected script] line=[1] lineSource=[return doSubmit()] lineOffset=[7]

当我使用

htmlForm.getInputByName("Restore").click();

什么都没发生

Answer 1

代码正在运行，过载消失了。但是我运行在 spring 容器中进行测试，由于某种原因我得到了这个错误。

@RunWith(SpringRunner.class)
@SpringBootTest

如果你运行没有 spring 一切正常。

htmlForm.<HtmlFileInput>getInputByName("filename").setValueAttribute(model);
htmlForm.<HtmlFileInput>getInputByName("filename").setContentType("multipart/form-data");
HtmlPage restore = htmlForm.getInputByName("Restore").click();

刷新

问题是 - “目标服务器无法响应异常。” 我在

中避免了这种情况

        webClient.getOptions().setTimeout(20000);
        webClient.getOptions().setThrowExceptionOnScriptError(false);
        webClient.getOptions().setThrowExceptionOnFailingStatusCode(false);
        webClient.getOptions().setCssEnabled(false);
        webClient.getOptions().setJavaScriptEnabled(true);
        webClient.getOptions().setUseInsecureSSL(true);
        webClient.getOptions().setRedirectEnabled(true);

决定

如何使用 HtmlUnit 以表单形式提交文件

How to submit file in form with HtmlUnit

java

htmlunit