带有填充有 SQL 值的复选框的 ListView

Question

我在我的 Android 项目中创建了 SQL 数据库，并设法用我插入的数据填充 ListView。该项目的下一部分是为我的 ListView 中的每个项目（来自 SQL 数据库）启用复选框。我找到了一种方法来处理字符串值，但我不确定如何处理 SQL 数据库中的值。

是否可以将 SQL 值放入 String 中？或者我需要使用不同的数据值来填充我的 ListView ？

我对 Android 中的 SQL 仍然很陌生，所以每个建议都会有所帮助。

代码如下：

public class ModelBreakfast {

public String name; //This String need to be filled with SQL datas. If it's possible. 
public boolean checked;

public ModelBreakfast(String name, boolean checked){
    this.name = name;
    this.checked = checked;
}
}

只是想说我尝试用我的 ContractClass 替换 public String name; public FoodContract.FoodEntry entry; 我在其中为我的数据库行定义了所有字符串值。（_ID、姓名等）。（我只看到了解决我的问题的方法）。所以，代码现在看起来像这样：

public ModelBreakfast(FoodContract.FoodEntry entry, boolean checked){
    this.entry = entry;
    this.checked = checked;
}

下一个 class 是 CustomAdapter

public class CustomAdapterBreakfast extends ArrayAdapter<ModelBreakfast> {

private ArrayList<ModelBreakfast> dataSet;
Context mContext;

private static class ViewHolder {
    TextView txtName;
    CheckBox checkBox;
}

public CustomAdapterBreakfast(ArrayList<ModelBreakfast> data, Context context){
    super(context, R.layout.activity_breakfast_checkbox, data);
    this.dataSet = data;
    this.mContext = context;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {

    ViewHolder viewHolder;
    final View result;

    if (convertView == null) {
        viewHolder = new ViewHolder();
        convertView = LayoutInflater.from(parent.getContext()).inflate(R.layout.activity_breakfast_checkbox, parent, false);
        viewHolder.txtName = (TextView) convertView.findViewById(R.id.txtName);
        viewHolder.checkBox = (CheckBox) convertView.findViewById(R.id.checkBox);

        result=convertView;
        convertView.setTag(viewHolder);

    } else {
        viewHolder = (ViewHolder) convertView.getTag();
        result=convertView;
    }

    ModelBreakfast item = getItem(position);

    viewHolder.txtName.setText(item.name); //Need to replace or modify this part
    viewHolder.checkBox.setChecked(item.checked);

    return  result;
}}

最后一部分是 MainActivity

public class BreakfastActivity extends AppCompatActivity {
ArrayList<ModelBreakfast> modelBreakfastArrayList;
private CustomAdapterBreakfast customAdapterBreakfast;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_breakfast);

    ListView listView = (ListView) findViewById(R.id.listBreakfast);

    modelBreakfastArrayList = new ArrayList<>();

    modelBreakfastArrayList.add(new ModelBreakfast("This string will show in ListView. So I need to somehow replace that String with SQL datas.", false));

    customAdapterBreakfast = new CustomAdapterBreakfast(modelBreakfastArrayList, getApplicationContext());
    listView.setAdapter(customAdapterBreakfast);

    listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

            ModelBreakfast modelBreakfast= modelBreakfastArrayList.get(position);
            modelBreakfast.checked = !modelBreakfast.checked;
            customAdapterBreakfast.notifyDataSetChanged();
        }
    });
}}

在我用我的 ContractClass public FoodContract.FoodEntry entry; 替换 public String name; 之后，我明白我不能使用

modelBreakfastArrayList.add(new ModelBreakfast("This string will show in ListView", false));。但是我需要设置什么，所以我的带复选框的 ListView 将显示我的 SQL 数据库值？

Should I use ArrayList instead String? And how?

Answer 1

还是我之前在上一个问题中说的。查看 for 循环。因此，在您的 SQLDB Activity 中以及从数据库中获取值的函数中，您需要填充一个数组列表，您将在 MainActivity.

中调用该列表

public ArrayList<String> getAirportRegion(String code)
    Cursor cursor = db.rawQuery("SELECT "+ AIRPORT_NAME +
            " FROM " + AIRPORT_TABLE + " WHERE " + AIRPORT_CODE + " = " + code, null);
    if (cursor.moveToFirst()) {
        while (!cursor.isAfterLast()) {
            arrayList.add(cursor.getString(cursor.getColumnIndex(AIRPORT_NAME)));
            cursor.moveToNext();
        }
    }
    cursor.close();
    return arrayList;
}

现在在 Main Activity 中获取对数据库的引用并将其设置为 modelBreakfastArrayList，就像这样

airportArrayList = mdb.getAirportRegion();

瞧，完成了

你看到我是如何提取数据的了吗？在大多数情况下，这是从本地数据库中提取列表的最佳方式。将这些活动分开，我也希望您将数据库 activity 作为单例，否则，您将拥有多个数据库，这会消耗资源。在下面查看我如何开始这些数据库活动。

private DBHelper(Context context) {
    super(context, "db", null, DATABASE_VERSION);
}

private static DBHelper INSTANCE;

public static DBHelper getInstance(Context context) {
    if (INSTANCE == null) {
        INSTANCE = new DBHelper(context);
    }
    return INSTANCE;
}

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