接下来如何创建条件，即使错误是 "the index out of range"

Question

这是我第一次使用 python，我还在学习 python。我在尝试使用索引时遇到问题。索引显示错误 "IndexError: list index out of range"。但我想通过或为它创造条件。像这样的例子：

    links = "http://www.website_name.com/"
    content_ig = BeautifulSoup(send.content, 'html.parser')
    script = content_ig.find_all("script")[3].get_text()
    script  = script.split('openData = ')[1][:-1]
    if not script:
        #This condition i create to next if the value is out of index
    else:
        print("Works")

我的意思是当索引超出范围时，我想在另一个值旁边创建条件，而不仅仅是停止并显示错误 "IndexError: list index out of range"。

Answer 1

为了解决您的问题，您可以将代码行包裹在 try-except 大括号内：

try:
    script  = script.split('openData = ')[1][:-1]
    print("Works")
except IndexError:
    ... # code to run if the value is out of index

快速演示：

In [1739]: x = [0]

In [1740]: try:
      ...:     print(x[1]) # only 1 element in x, so this is invalid 
      ...: except IndexError:
      ...:     print("List out of range!")
      ...:     
List out of range!

接下来如何创建条件，即使错误是 "the index out of range"

How to create condition next even the error is "the index out of range"

indexing

beautifulsoup

next

python-3.x