SQL 服务器分区顺序 - 即使行相同也不会绑定 DenseRank 值

Question

这个问题最好用一张图片和我目前拥有的脚本来解释...我如何才能在每次分配时提取完整的一行，排名最低，并且如果有 2 行的 denserank 为 1，然后选择其中一个？...

select *
,Dense_RANK() over (partition by [Assignment] order by [Text] desc) as 
[DenseRank]
 from  [dbo].[CLEANSED_T3B_Step1_Res_Withdups____CP]




select * from
(
select *
,Dense_RANK() over (partition by [Assignment] order by [Text] desc, NewID() 
) as [DenseRank] from  [dbo].[CLEANSED_T3B_Step1_Res_Withdups____CP]
 ) as A
 where A.[DenseRank] = 1

第二个脚本运行完美！

SELECT * INTO 
[dbo].[CLEANSED_T3B_Step1_COMPLETED]
from
(
  select *
    ,Dense_RANK()                   over (partition by [Assignment] order by 
 left([Text],1) desc , [Diff_Doc_Clearing_Date] desc , [Amount] asc
as [DenseRank] 
 from  [dbo].[CLEANSED_T3B_Step1_Res_Withdups____CP] 
 )  
as A
 where A.[DenseRank] = 1

不再只需要一个随机的第一名并列“第一名”，现在需要获得最高日差的那个，然后也是最高的。所以在这个版本 3 中调整了所有内容。

Answer 1

您似乎不想使用 DENSE_RANK 但 ROW_NUMBER.

with cte as(
   select t.*, rn = row_number() over(partition by assignment order by [text] desc) 
   from tablename t
)
select * from cte 
where rn = 1

Answer 2

按 'newid()' 作为 'tie-breaker'

排序

Order by [Text],Newid()

SQL 服务器分区顺序 - 即使行相同也不会绑定 DenseRank 值

SQL Server Partition Order - No tie DenseRank values even if rows are same

sql

sql-server

partition