C++函数没有返回值

Question

这是我的代码，我不明白为什么当 main() 中的确切代码产生正确答案时它不能作为函数工作。作业是将二进制数转换为十进制数。

#include <iostream>
#include <cstdlib>
#include "std_lib_facilities.h"
using namespace std;
int binaryCon(int biNum);
int main()
{
    int num, bin, Bnum;
    cout << "Enter the binary number(1s and 0s) : ";
    cin >> num;
    bin = num;
    Bnum = binaryCon(num);
    cout << "The decimal equivalent of " << bin << " : " << Bnum << endl;
}
    int binaryCon(int biNum)
{
    long dec = 0, rem = 0, base = 1;
    enter code here`while (biNum > 0)
    rem = biNum % 10;
    dec = dec + rem * base;
    base = base * 2;
    biNum = biNum / 10;

    return biNum;
}

Answer 1

因为您没有在 while 循环中使用 { 和 } 可能会进入无限循环。因为它只适用于这条线

while (biNum > 0)
    rem = biNum % 10;    // running this line infinite as `biNum > 0`

使用

while (biNum > 0){
    rem = biNum % 10;
    dec = dec + rem * base;
    base = base * 2;
    biNum = biNum / 10;
}

Answer 2

也许是这个？

while (biNum > 0)
{
    rem = biNum % 10;
    dec = dec + rem * base;
    base = base * 2;
    biNum = biNum / 10;
}

Answer 3

更正代码：

#include <iostream>
#include <cstdlib>
using namespace std;
int binaryCon(int biNum);
int main()
{
    int num, bin, Bnum;
    cout << "Enter the binary number(1s and 0s) : ";
    cin >> num;
    bin = num;
    Bnum = binaryCon(num);
    cout << "The decimal equivalent of " << bin << " : " << Bnum << endl;
    getchar();
    return 0;
}
int binaryCon(int biNum)
{
    long dec = 0, rem = 0, base = 1;
    while (biNum > 0){
        rem = biNum % 10;
        dec = dec + rem * base;
        base = base * 2;
        biNum = biNum / 10;
    }
    return dec;
}

Answer 4

int main() 或 int main(int argc, char** argv) 必须 return 一个值。如果你return0那么说明代码没有问题。另一个数字 1,2 etc 表示有错误。（返回的数字是错误数字）

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