错误是 'int' object is not iterable，我正在 python 中做一个小项目，允许用户输入十个学生的名字和十个年龄

Question

print("\n")
print("Please input ten student names and their ages as well")
print("\n")
print("Student Names: \t\t\t\t Student Ages: ")
print("------------------- \t\t\t\t -------------------")
print("\n")
studentNames =[]
for element in range(10):
    element = input("Please input 10 student names: ")
    input_ages = int(input("\t\t\t\t\tNow please input their ages as well: "))

team_leader = max(input_ages)

print(team_leader)

Answer 1

for element in range(10):
    ...
    input_ages = int(input("\t\t\t\t\tNow please input their ages as well: "))

team_leader = max(input_ages)

input_ages 是一个整数，每次循环迭代都会重新分配。

max(input_ages) 期望 input_ages 是一个列表，通过遍历它来找到最大值。因此你得到 'int' object is not iterable.

要正确执行此操作，请在循环之前初始化一个空列表 input_ages，然后在循环中将年龄附加到该列表：

input_ages = []
for element in range(10):
    ...
    input_ages.append(int(input("\t\t\t\t\tNow please input their ages as well: ")))

team_leader = max(input_ages)

Answer 2

根据您所写的内容：

Displays info
Makes empty list studentsNames
Repeats the following 10 times:
 Asks the user for ten names and put the string in a variable
 Asks the user for the ten ages and tries to turn a string to an integer* and stores that in a variable
 Each loop, the variables are overwritten
Gets the highest value from the age variable which would be the last and only one, saves it to a variable
Display that variable

*你必须给每个学生输入一个循环，否则你会出错。

但是我想你会想做这样的事情。我继续使用两个列表，但我认为会有更好的方法来存储数据。

print("your info")
names = []
ages = []
for __ in range(10):
    name.append(input("Enter student name: "))
    age.append(int(input("Age: ")))
oldest_age = max(ages)
index = ages.index[oldest_age]
team_leader = names[index]
print(team_leader)

错误是 'int' object is not iterable，我正在 python 中做一个小项目，允许用户输入十个学生的名字和十个年龄

the error is 'int' object is not iterable, I am working on a small project in python that allows the user to input ten names and ten ages of students

python

python-3.6