检查月份中的某一天是否在两个月之间

Question

我想检查 (month,day) 是否在两个月之间 ，而不考虑年份 。我在为 1 月 月份建模时遇到问题。我试着在 13 号之前代表 1 月，但我卡住了。

return 值

3 = 6 月 25 日至 8 月 22 日之间
2 = 在 01APR-24JUN 或 22AUG-31OCT 或 17DEC-01JAN 之间
1 = 在 01SEP-31MAR 或 01NOV-16DEC 或 02JAN-31MAR 之间
0 = 我的程序不工作，找不到日期。我完蛋了

源代码

from datetime import date, datetime, timedelta

def get_season(date):
        month = date.month
        day   = date.day
        
        if month == 1:
            month = 13
        
        if (6,25) <= (month, day) <= (8,22):
            return 3
        
        elif (4, 1) <= (month, day) <= (6,24) or (8, 22) < (month, day) <= (10, 31) or (12,17) <= (month, day) <= (13,1):
            return 2
        
        elif  (9, 1) <= (month, day) <= (3, 31) or  (11,1) <= (month, day) <= (12, 16) or (13,2) <= (month, day) <= (3, 31):
            return 1
        else:
            return 0
        
if __name__ == "__main__":
    
    date = datetime.strptime("2016-02-01",'%Y-%m-%d').date()
    
    if get_season(date) == 0:
      print "WRONG DOES NOT EXIST THERE!!!!!!!!!!!!!!"

Answer 1

我会直接在 datetime.date 个对象之间进行所有这些比较，然后将它们重写为一年。

from datetime import date

def get_season(d):

    d = date(year=1900, month=d.month, day=d.day)

    if date(1900, 6, 25) <= d <= date(1900, 8, 22):
        return 3

    elif date(1900, 4, 1) <= d <= date(1900, 6, 24) or \
         date(1900, 8, 22) <= d <= date(1900, 10, 31) or \
         date(1900, 12, 17) <= d <= date(1900 12, 31) or \
         date(1900, 1, 1) == d:
        return 2

    elif date(1900, 9, 1) <= d <= date(1900, 3, 31) or \
         date(1900, 11, 1) <= d <= date(1900, 12, 16) or \
         date(1900, 1, 2) <= d <= date(1900, 3, 31):
        return 1

这也使得创建边界对变得更加容易。

def get_season(d):
    d = date(year=1900, month=d.month, day=d.day)

    boundarydict = {1: [(date(1900, 9, 1), date(1900, 3, 31)),
                        (date(1900, 11, 1), date(1900, 12, 16)),
                        (date(1900, 1, 2), date(1900, 3, 31))],
                    2: [(date(1900, 4, 1), date(1900, 6, 24)),
                        (date(1900, 8, 22), date(1900, 10, 31)),
                        (date(1900, 12, 17), date(1900, 12, 31)),
                        (date(1900, 1, 1), date(1900, 1, 1))], # note this one!
                    3: [(date(1900, 6, 25), date(1900, 8, 22))]}

    for retval, boundaries in boundarydict.values():
        if any(a <= d <= b for a, b in boundaries):
            return retval

检查月份中的某一天是否在两个月之间

check if day of month is between two months

python

python-datetime

return 值

源代码