使用 AutoMapper 映射实体

Mapping entity with AutoMapper

我正在尝试使用 auto mapper(ver 6.1.1.0)

映射两个实体

类 我正在测试

public class Person
{
    public int Id { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public string Add1 { get; set; }
    public string Add2 { get; set; }
}

public class Employee
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public Address Address { get; set; }
}

public class Address
{
    public string Address1 { get; set; }
    public string Address2 { get; set; }

}
   public class Entity
{
    public int Id { get; set; }
    public string Title { get; set; }
}

我想将 Person 映射到 Employee。我在下面尝试过但不确定如何让它工作

private void MapperTest()
{
    Mapper.Initialize(cfg =>
    {
        cfg.CreateMap<Person, Employee>()
        .ForMember(e => e.Address,
                   p => p.MapFrom(a => a.Address1))
                });

    var person = new Person { Id = 100, FirstName = "Rob", LastName = "Wood", Add1="Address line 1",Add2 = "Address line 2" ,CountryId =100,Country="UK"};
}

更新,如果 Address 实体包含另一个实体 属性 我在下面尝试过

Mapper.Initialize(cfg => {

                cfg.CreateMap<Person, Address>()
              .ForMember(a => a.Address1, opt => opt.MapFrom(p => p.Add1))
              .ForMember(a => a.Address2, opt => opt.MapFrom(p => p.Add2));
                    cfg.CreateMap<Person, Employee>()
                            .ForMember(e => e.Address,
                                       opt => opt.MapFrom(p => p))
                            .ForMember(b => b.Address.Country,
                            opt => opt.MapFrom(br => br));
            });

这应该有效:

cfg.CreateMap<Person, Address>()
        .ForMember(a => a.Address1, opt => opt.MapFrom(p => p.Add1))
        .ForMember(a => a.Address2, opt => opt.MapFrom(p => p.Add2));
cfg.CreateMap<Person, Employee>()
        .ForMember(e => e.Address,
                   opt => opt.MapFrom(p => p));

简短说明:您将映射从 Person 拆分为 2 个实体,并告诉映射器 AddressEmployee

的子项

试试这个

cfg.CreateMap<Person, Employee>()  .ForMember(e => e.Address, p => p.MapFrom(a => new Address{Address1=a.Address1, Address2=a.Address2 }) });