SQL STUFF 函数汇总多行

Question

我想在同一天进行输入时合并一个字段。用户可以在同一天为给定的源多次输入一条消息。结果 table 如下 -

我想做的是在同一天将 MessageText 与 SourceID 组合在一起。

我有它，它将在同一天为 SourceID 创建记录，但是无论日期是什么，它都会为 SourceID 放置每个 MessageText。它确实在同一天给出一行。例如，SourceID 在 2012-11-08 有 2 个条目，在 2017-07-11 有 1 个条目。它为 2012-11-08 创建一行，为 2017-07-11 创建一行，但是它将所有 3 MessageText 放在行中。

我的代码是 -

SELECT distinct  s.SourceID, stuff ( (select ', ' + rtrim(x.MessageText)
                                            from [AVData].[dbo].[LogCentralMessageData] x
                                            inner join AVData.[dbo].[Source] a on a.SourceID = t.SourceID
                                            inner join(select distinct max(m.CreatedOn)over (partition by r.SourceSiteID, Convert(date, m.CreatedOn)) as maxDate, r.SourceSiteID
                                                from [AVData].[dbo].[LogCentralMessageData] m 
                                                left join AVData.[dbo].[Source] r on r.SourceID = m.SourceID
                                                )  t on t.SourceSiteID = a.SourceSiteID and convert(date, t.maxDate) = Convert(date, x.CreatedOn)

                                            where x.SourceID = a.SourceID  

                                            for XML path('')), 1, 1, '') message_text
        ,convert(date, t.CreatedOn) as CreatedDate


from [AVData].[dbo].[LogCentralMessageData] t

left join AVData.[dbo].[Source] s on s.SourceID = t.SourceID
order by SourceID, CreatedDate

Answer 1

SELECT SourceID, cast(CreatedOn as date) as CreatedDate,  message_text = STUFF(
             (SELECT ',' + MessageText 
              FROM yourtable t1
              WHERE t1.id = t2.id
              FOR XML PATH (''))
             , 1, 1, '') from yourtable t2
group by SourceID, cast(CreatedOn as date);

Answer 2

下面应该可以解决问题...

SELECT 
    st1.SourceID,
    CAST(st1.CreatedOn AS DATE)
    message_text = STUFF(
                (SELECT 
                    CONCAT(', ', st2.MessageText)
                FROM 
                    dbo.SomeTable st2
                WHERE 
                    st1.SourceID = st2.SourceID
                    AND CAST(st1.CreatedOn AS DATE) = CAST(st2.CreatedOn AS DATE)
                ORDER BY 
                    st2.CtreatedOn
                FOR XML PATH ('')
                ), 1, 2, '')
FROM 
    dbo.SomeTable st1
GROUP BY 
    st1.SourceID,
    CAST(st1.CreatedOn AS DATE);

Answer 3

在使用 stuff() 时要记住一件事，它需要四个参数 stuff(Query for xml path(''),1,1,'')。你可以像那样使用 stuff() -

stuff((select +'/'+(CASE WHEN t2.Name IS NOT NULL THEN t2.Name ELSE (ISNULL(t2.FirstName,'') + ' ' + ISNULL(t2.LastName,'')) END)
                  from table2 t2 inner join table1 MR on t2.id = mr.id
                  where t2.ContactId = m2.contactid for xml path('')),1,1,'')

SQL STUFF 函数汇总多行

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