从 gtk3 中的输入创建信号，python，raspberry pi

Question

我在 raspberry pi3 上制作了一个 gui 程序，我想从输入端 (gpio) 获取信号以执行一些命令，例如按下按钮时会生成信号。我想从输入中获取此信号。代码是

import time
import gi
import  RPi.GPIO as GPIO
gi.require_version('Gtk', '3.0')
from gi.repository import Gtk
GPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(18, GPIO.IN,pull_up_down=GPIO.PUD_DOWN)

class gui:
  inputValue = GPIO.input(18)
  if inputValue == True:
    self.label.set_text("There is input")
  def on_window1_destroy(self, object, data=None):
    print( "quit with cancel")
    Gtk.main_quit()
  def on_okButton_clicked(self,button,data=None):
    self.label.set_text("Waiting for input")
  def __init__(self):
    self.gladefile = "2.glade"
    self.builder = Gtk.Builder()
    self.builder.add_from_file(self.gladefile)
    self.builder.connect_signals(self)
    self.window = self.builder.get_object("window1")
    self.label = self.builder.get_object("Label")
    self.label.set_text("Hello")
    self.window.show_all()

if __name__ == "__main__":
  main = gui()
  Gtk.main()

输入仅在执行开始时进行，当我使用循环时 window 冻结。请帮我。谢谢。

Answer 1

我的 PI 藏在一个盒子里。此代码未经测试，仅在我的脑海中。告诉我它是否有效。

import time
import gi
import  RPi.GPIO as GPIO
gi.require_version('Gtk', '3.0')
from gi.repository import Gtk
GPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(18, GPIO.IN,pull_up_down=GPIO.PUD_DOWN)

class gui:
  def pin_callback (self, channel):
    print ('pressed')
  def on_window1_destroy(self, object, data=None):
    print( "quit with cancel")
    Gtk.main_quit()
  def on_okButton_clicked(self,button,data=None):
    self.label.set_text("Waiting for input")
  def __init__(self):
    self.gladefile = "2.glade"
    self.builder = Gtk.Builder()
    self.builder.add_from_file(self.gladefile)
    self.builder.connect_signals(self)
    self.window = self.builder.get_object("window1")
    self.label = self.builder.get_object("Label")
    self.label.set_text("Hello")
    self.window.show_all()
    GPIO.add_event_detect(18, GPIO.BOTH, callback=self.pin_callback)

if __name__ == "__main__":
  main = gui()
  Gtk.main()

Answer 2

我通过如下编辑代码解决了这个问题：

import time
import gi
import  RPi.GPIO as GPIO
gi.require_version('Gtk', '3.0')
from gi.repository import Gtk
GPIO.setmode(GPIO.BCM)
GPIO.setwarnings(False)
GPIO.setup(18, GPIO.IN,pull_up_down=GPIO.PUD_DOWN)

class gui:

  def pin_callback (self, channel):
    print ('pressed')
    self.label.set_text("INput")

  def on_window1_destroy(self, object, data=None):
    print( "quit with cancel")
    Gtk.main_quit()
  def on_okButton_clicked(self,button,data=None):
    self.label.set_text("Waiting for input")
  def __init__(self):
    self.gladefile = "m.glade"
    self.builder = Gtk.Builder()
    self.builder.add_from_file(self.gladefile)
    self.builder.connect_signals(self)
    self.window = self.builder.get_object("window1")
    self.label = self.builder.get_object("Label")
    self.label.set_text("Hello")
    self.window.show_all()

if __name__ == "__main__":
  main = gui()
  GPIO.add_event_detect(18, GPIO.BOTH, callback=main.pin_callback)
  Gtk.main()

非常感谢你，theGtknerd。

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