禁用在后台点击时关闭弹出框 Swift

Question

我有一个名为 TestViewController 的主视图控制器，它有一个按钮，当您点击该按钮时，它会打开一个弹出视图控制器。当您点击背景时，弹出窗口会消失，这是我想要禁用的。我的弹出视图控制器中有这段代码，它应该运行但不是运行ning.

extension TestViewController: UIPopoverPresentationControllerDelegate {

    func popoverPresentationControllerShouldDismissPopover(_ popoverPresentationController: UIPopoverPresentationController) -> Bool {
        print ("TEST") //This does not show up in console

        return false
    }
}

编辑：

这是我用来打开弹出窗口的代码。

let popover = storyboard?.instantiateViewController(withIdentifier: "PopoverVC") as! PopOverViewController

        popover.modalPresentationStyle = .popover

        popover.popoverPresentationController?.sourceView = self.view
        popover.popoverPresentationController?.sourceRect = CGRect(x: self.view.bounds.midX, y: self.view.bounds.midY, width: 0, height: 0)

        popover.popoverPresentationController?.permittedArrowDirections = UIPopoverArrowDirection(rawValue: 0)


        popoverPresentationController?.passthroughViews = nil

        popover.dimView2 = self.dimView2

        dimView2.isHidden = false

        self.present(popover, animated: false)

    }

Answer 1

设置委托。

popover.popoverPresentationController?.delegate = self

Answer 2

popoverPresentationControllerShouldDismissPopover 函数在 iOS 14.

中已弃用

对于最新版本，您应该使用以下代码

extension TestViewController: UIPopoverPresentationControllerDelegate {
        func presentationControllerShouldDismiss(_ presentationController: UIPresentationController) -> Bool {
             return false
        }
    }

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