Python 随机十六进制生成器

Question

所以我希望在每次调用时生成一个随机的十六进制值

randhex = "\x" + str(random.choice("123456789ABCDEF")) + str(random.choice("123456789ABCDEF"))

到目前为止，我所想到的就是进行不同的 = 调用（例如 randhex1 = ^^、randhex2）等等，但那既乏味又低效，我不想这样做

ErrorClass = "\x" + str(random.choice("123456789ABCDEF")) + "\x" + str(random.choice("123456789ABCDEF")) + "\x" + str(random.choice("123456789ABCDEF")) + "\x" + str(random.choice("123456789ABCDEF"))

因为这看起来不太好，而且很难说出有多少。

我正在尝试将它分配给这个

ErrorClass = randhex1 + randhex2 + randhex3 + randhex4,
Flags = randhex5,
Flags2 = randhex6 + randhex7,
PIDHigh = randhex2 + randhex5,

理想情况下，我希望它们全部统一，或者像 ErrorClass = randhex*4 这样干净的东西，而不是必须分配不同的数字。但是，如果我这样做，它只是将代码复制为如下所示：

Input: ErrorClass = randhex + randhex + randhex + randhex
Output: \xFF\xFF\xFF\xFF

这显然是行不通的，因为它们都是一样的。任何帮助都会很棒。

Answer 1

创建一个函数，returns 随机生成的字符串。每次调用它都会给你一个新的值。

import random

def randhex():
    return "\x" + str(random.choice("0123456789ABCDEF")) + str(random.choice("0123456789ABCDEF"))

ErrorClass = randhex() + randhex() + randhex() + randhex()
Flags = randhex()
Flags2 = randhex() + randhex()
PIDHigh = randhex() + randhex()

print(ErrorClass)
print(Flags)
print(Flags2)
print(PIDHigh)

示例结果：

\xBF\x2D\xA2\xC2
\x74
\x55\x34
\xB6\xF5

为了更加方便，向 randhex 添加一个 size 参数，这样您就不必在每次赋值时多次调用它：

import random

def randhex(size=1):
    result = []
    for i in range(size):
        result.append("\x" + str(random.choice("0123456789ABCDEF")) + str(random.choice("0123456789ABCDEF")))
    return "".join(result)

ErrorClass = randhex(4)
Flags = randhex()
Flags2 = randhex(2)
PIDHigh = randhex(2)

print(ErrorClass)
print(Flags)
print(Flags2)
print(PIDHigh)

Python 随机十六进制生成器

Python random hex generator

python

random

smb

hex

python-2.7