SQL ORACLE DB 左连接的替代方法

Question

如果我运行查询下面的查询：

SELECT day.M_CMP_TYPO AS M_CMP_TYPO,
        day.M_SPTCV as M_SPTCV,
       day.M_CNT_VS2 AS M_CNT_VS2,
       day.M_CNT_ORG AS M_CNT_ORG,
       day.M_PL_CGR2 AS M_PL_CGR2,
       day.M_PL_CGU2 AS M_PL_CGU2,
       day.M_PL_CSFI2 AS M_PL_CSFI2,
       day.M_PL_FTFI2 AS M_PL_FTFI2,
       day.M_PL_RVR2 AS M_PL_RVR2,
       day.M_PL_RVU2 AS M_PL_RVU2,
       day.M_TRN_FMLY AS M_TRN_FMLY,
       day.M_TRN_GRP AS M_TRN_GRP,
       day.M_TRN_TYPE AS M_TRN_TYPE,
       day.M_CNT_VS2 AS M_CNT_VS2,
       day.M_C_CUR_PL AS M_C_CUR_PL,
       day.M_INSTRLABEL AS M_INSTRLABEL,
       day.M_NB AS M_NB,
       day.M_PL_INSCUR AS M_PL_INSCUR,
       day.M_TP_CNTRPLB AS M_TP_CNTRPLB,
       day.M_TP_PFOLIO AS M_TP_PFOLIO,
       day.M_ECO_PL AS M_ECO_PL,
       day.M_CNT_ID AS M_CNT_ID,
       day.M_ECO_PL_USD AS M_ECO_PL_USD,
       day.M_POS_CURR2 AS M_POS_CURR2,
       day.M_CURR2 AS M_CURR2,
       day.M_TP_QTYEQ AS M_TP_QTYEQ,
       day.M_TP_UQTYEQ AS M_TP_UQTYEQ,
       day.M_TP_LQTY32 AS M_TP_LQTY32,
       day.M_TP_UQTY AS M_TP_UQTY,


     --day.M_ECO_PL - daily.M_ECO_PL AS DAILY_VAR,
         --day.M_ECO_PL - month.M_ECO_PL AS MTD,
     day.M_ECO_PL - year.M_ECO_PL AS YTD,



--day.M_SPTCV * (day.M_ECO_PL - daily.M_ECO_PL) as DAILY_VAR_USD,
--day.M_SPTCV * (day.M_ECO_PL - month.M_ECO_PL) as MTD_USD,
day.M_SPTCV * (day.M_ECO_PL - year.M_ECO_PL) as YTD_USD



  FROM RT_PLVAR_REP day
  LEFT JOIN RT_PLVAR_REP year ON day.M_NB = year.M_NB
    --LEFT JOIN RT_PLVAR_REP month ON day.M_NB = month.M_NB
  --LEFT JOIN RT_PLVAR_REP daily ON day.M_NB = daily.M_NB

WHERE day.M_REF_DATA = 18
AND   year.M_REF_DATA = 20
--AND   month.M_REF_DATA = 0
--AND   daily.M_REF_DATA = 0

它 return 是预期的行为，这意味着它 return 27 行知道 year.M_REF_DATA = 20 存在于数据库中。否则如果我运行这个我没有价值。由于 M_REF_DATA=0 在 table 中不存在，我期望此查询 returns 27 行，但相关列应该 return 为空，但这不是案例.

我试过将 Where 替换为 AND 它也没有用。它 returned 1728 行，这是一个错误的答案，它应该 return 11. 我的问题是为什么左连接没有像我期望的那样工作？

SELECT day.M_CMP_TYPO AS M_CMP_TYPO,
            day.M_SPTCV as M_SPTCV,
           day.M_CNT_VS2 AS M_CNT_VS2,
           day.M_CNT_ORG AS M_CNT_ORG,
           day.M_PL_CGR2 AS M_PL_CGR2,
           day.M_PL_CGU2 AS M_PL_CGU2,
           day.M_PL_CSFI2 AS M_PL_CSFI2,
           day.M_PL_FTFI2 AS M_PL_FTFI2,
           day.M_PL_RVR2 AS M_PL_RVR2,
           day.M_PL_RVU2 AS M_PL_RVU2,
           day.M_TRN_FMLY AS M_TRN_FMLY,
           day.M_TRN_GRP AS M_TRN_GRP,
           day.M_TRN_TYPE AS M_TRN_TYPE,
           day.M_CNT_VS2 AS M_CNT_VS2,
           day.M_C_CUR_PL AS M_C_CUR_PL,
           day.M_INSTRLABEL AS M_INSTRLABEL,
           day.M_NB AS M_NB,
           day.M_PL_INSCUR AS M_PL_INSCUR,
           day.M_TP_CNTRPLB AS M_TP_CNTRPLB,
           day.M_TP_PFOLIO AS M_TP_PFOLIO,
           day.M_ECO_PL AS M_ECO_PL,
           day.M_CNT_ID AS M_CNT_ID,
           day.M_ECO_PL_USD AS M_ECO_PL_USD,
           day.M_POS_CURR2 AS M_POS_CURR2,
           day.M_CURR2 AS M_CURR2,
           day.M_TP_QTYEQ AS M_TP_QTYEQ,
           day.M_TP_UQTYEQ AS M_TP_UQTYEQ,
           day.M_TP_LQTY32 AS M_TP_LQTY32,
           day.M_TP_UQTY AS M_TP_UQTY,


         day.M_ECO_PL - daily.M_ECO_PL AS DAILY_VAR,
             day.M_ECO_PL - month.M_ECO_PL AS MTD,
         day.M_ECO_PL - year.M_ECO_PL AS YTD,



    day.M_SPTCV * (day.M_ECO_PL - daily.M_ECO_PL) as DAILY_VAR_USD,
    day.M_SPTCV * (day.M_ECO_PL - month.M_ECO_PL) as MTD_USD,
    day.M_SPTCV * (day.M_ECO_PL - year.M_ECO_PL) as YTD_USD



      FROM RT_PLVAR_REP day
      LEFT JOIN RT_PLVAR_REP year ON day.M_NB = year.M_NB
        LEFT JOIN RT_PLVAR_REP month ON day.M_NB = month.M_NB
      LEFT JOIN RT_PLVAR_REP daily ON day.M_NB = daily.M_NB

    WHERE day.M_REF_DATA = 18
    AND   year.M_REF_DATA = 0
    AND   month.M_REF_DATA = 0
    AND   daily.M_REF_DATA = 0

Answer 1

这是第一个查询中的 from 和 where 子句：

FROM RT_PLVAR_REP day LEFT JOIN
     RT_PLVAR_REP year
     ON day.M_NB = year.M_NB
WHERE day.M_REF_DATA = 18 AND year.M_REF_DATA = 20

where 子句将 LEFT JOIN 转换为 INNER JOIN。 year.M_REF_DATA 的值为 NULL，因此不符合条件。

对于 LEFT JOIN，条件应该放在 ON 子句中：

FROM RT_PLVAR_REP day LEFT JOIN
     RT_PLVAR_REP year
     ON day.M_NB = year.M_NB AND year.M_REF_DATA = 20
WHERE day.M_REF_DATA = 18

第一个table的条件应该留在WHERE。

Answer 2

对于外部联接，您需要将筛选条件移动到联接：

  FROM RT_PLVAR_REP day
  LEFT JOIN RT_PLVAR_REP year 
    ON day.M_NB = year.M_NB
       AND year.M_REF_DATA = 0
  LEFT JOIN RT_PLVAR_REP month 
    ON day.M_NB = month.M_NB
       AND month.M_REF_DATA = 0
  LEFT JOIN RT_PLVAR_REP daily 
    ON day.M_NB = daily.M_NB
       AND daily.M_REF_DATA = 0
WHERE day.M_REF_DATA = 18

这告诉数据库您只想在存在行时强制执行该条件。

SQL ORACLE DB 左连接的替代方法

Alternative way to left join in SQL ORACLE DB

sql

oracle

select

left-join

where