我想做一个oracle查询但是我真的不熟悉，SQL错误信息[Err] ORA-00933: SQL command not properly ended

Question

我有一个 table customerordercapture 和一个列 updatedate。我想 select 在前一天（直到午夜）由客户在 customerordercapture table 中监控的实体，这是最后更新全天数据我还想要一个查询，我需要在倒数第二个更新日期之前的数据。查询是从脚本中触发的，因此硬编码日期将不起作用。

我认为我的查询是错误的。

SELECT distinct UPDATEDATE 
FROM customerordercapture 
GROUP BY UPDATEDATE 
HAVING MAX(UPDATEDATE) < = SYSDATE-2 
and UPDATEDATE >= MIN(UPDATEDATE) 
ORDER BY UPDATEDATE asc ;

SELECT distinct UPDATEDATE 
FROM customerordercapture
GROUP BY UPDATEDATE 
HAVING UPDATEDATE <= TRUNC(MAX(UPDATEDATE)) - INTERVAL '3' DAY 
and UPDATEDATE =TRUNC( MAX(UPDATEDATE) )
ORDER BY UPDATEDATE asc ;

Answer 1

如果我没看错的话，也许对你有帮助：

SELECT MAX(UPDATEDATE), some_column
FROM customerordercapture 
WHERE UPDATEDATE <= sysdate 
GROUP BY some_column
ORDER BY MAX(UPDATEDATE) asc;

我想做一个oracle查询但是我真的不熟悉，SQL错误信息[Err] ORA-00933: SQL command not properly ended

I would like to make a oracle query but I'm really not familiar with it, SQL error message[Err] ORA-00933: SQL command not properly ended

sql

oracle

date-arithmetic