一个简单的 Python 程序的缩进

Question

playerA=input("Please choose one from rock paper and scissors")
playerB=input("Please select one from rock paper and scissors")
if      playerA=rock and playerB=paper:
        print("player B wins")

elif playerA=scissor and playerB=paper:
         print("Player A wins, Congratulations Player A. Do you want to play 
        another game? ")

elif playerA=rock and playerB=rock:
         print("game is draw,  Do you want to play another game")

elif playerA=paper and playerB=paper:
         print("game is draw")

elif playerA=scissor and playerB=scissor:
         print("game is draw")

  elif playerA=paper and playerB=scissor: 
         print("Player B wins, Congratulations Player B. Do you want to play another game?") 

  elif playerA=scissor and playerB=rock:
         print("Player B wins, Congratulations Player B. Do you want to play another game?")

  elif  playerA=rock and playerB= scissor:
         print("Player A wins, Congratulations Player A. Do you want to play another game?")

  elif playerA=paper and playerB=rock:
         print("player A wins, Congratulations Player A. Do you want to play another game?")

请问我应该如何修复这里的缩进，我得到的错误是说 unindent 不匹配任何外部缩进级别。

Answer 1

您是否尝试过在 'if' 之后只输入 space 而不是制表符？

    if      playerA==rock and playerB==paper:

会变成：

    if playerA==rock and playerB==paper:

此外，您的倒数第二个 elif 还有一个 space。删除它也应该有所帮助。

Answer 2

您需要取消所有代码的缩进，然后使用制表符正确缩进。您混用了制表符和 spaces，这就是问题所在。

您还可以使用在 Python 安装的 Tools/scripts/ 目录中找到的 reindent.py 脚本。更改 Python (.py) 文件以使用 4-space 缩进并且没有硬制表符。还有 trim 多余的 space 和来自行尾的制表符。还要确保最后一行以换行符结尾。

Answer 3

删除此代码后 elif 之前的空白 space..

`elif playerA=paper and playerB=paper: 打印（"game is draw"）

elif playerA=scissor 和 playerB=scissor: 打印（"game is draw"）`

Answer 4

删除 else 语句。像这样

else only no statement is required

一个简单的 Python 程序的缩进

Indentation of a simple Python program

python

indentation