在 ASCII/UTF8 中转换带有重音符号的 Unicode 字母

Question

我正在寻找一种技术来转换由服务器发送的包含如下内容的字符串 (JSON)： ...."Test \u00e9\u00e9\u00e9"..... 类似于："Test ééé" 我找到了解决方案：boost::replace_all(listFolder, "\u00e9", "é"); 我正在将此增强功能与其他字母 àùèê 等一起使用....这很痛苦！

不知道有没有自动进行这种转换的函数

否则，我想告诉你一件事，如果我使用此功能，服务器将正确处理我发送给它并包含带重音符号的字母的字符串:

std::string fromLocale(std::string localeStr)
{
    boost::locale::generator g;
    g.locale_cache_enabled(true);
    std::locale loc = g(boost::locale::util::get_system_locale());
    return boost::locale::conv::to_utf<char>(localeStr,loc);
}

不幸的是，该代码的逆函数无法处理服务器发送的字符串。

std::string toLocale(std::string utf8Str)
{
    boost::locale::generator g;
    g.locale_cache_enabled(true);
    std::locale loc = g(boost::locale::util::get_system_locale());
    return boost::locale::conv::from_utf<char>(utf8Str,loc);
}

Answer 1

JSON specification 允许 Unicode 字符的 "\uXXXX" 序列（与其他 \X 转义序列一样）。如果您没有使用现有的 JSON 解析器来处理此类序列的解码，则必须手动解码它们，例如：

// JSON uses Unicode, but is commonly encoded as UTF-8. However, Unicode
// characters that are encoded in "\uXXXX" format are expressed as UTF-16
// codeunit values, using surrogate pairs for codepoint values U+10000 and
// higher. This example uses C++11's std::u16string to handle UTF-16 parsing.
// If you are not using C++11 or later, you can replace it with std::wstring
// on platforms where wchar_t is 16bit, for instance.  If you want to handle
// the JSON using std::string/UTF-8 instead, you will have to tweak this
// parsing accordingly...

std::u16string str = ...; // JSON quoted-string value, eg: "Test \u00e9\u00e9\u00e9"...
std::u16string::size_type idx = 0;
do
{
    idx = str.find(u'\', idx);
    if (idx == std::u16string::npos) break;

    std::u16string replaceStr;
    std::u16string::size_type len = 2;

    char16_t ch = str.at(idx+1);
    switch (ch)
    {
        case u'\"':
        case u'\':
        case u'/':
            replaceStr = ch;
            break;

        case u'b':
            replaceStr = u'\b';
            break;

        case u'f':
            replaceStr = u'\f';
            break;

        case u'n':
            replaceStr = u'\n';
            break;

        case u'r':
            replaceStr = u'\r';
            break;

        case u't':
            replaceStr = u'\t';
            break;

        case u'u':
        {
            std::u16string hexStr = str.substr(idx+2, 4);
            len += hexStr.size();

            std::basic_istringstream<char16_t> iss(hexStr);
            unsigned short value;
            iss >> std::hex >> value;
            if (!iss)
            {
                // illegal value, do something
            }

            replaceStr = (char_t) value;
            break;
        }

        default:
            // illegal sequence, do something
            break;
    }

    str.replace(idx, len, replaceStr);
    idx += replaceStr.size();
}
while (true);

Answer 2

我找到的解决方案是使用 RapidJson。

在 ASCII/UTF8 中转换带有重音符号的 Unicode 字母

converting Unicode letters with accents in ASCII/UTF8

c++

string

unicode

boost