如何检查单词是否在同义词集中？

Question

我正在尝试比较两个单词列表以检查是否：

word1 列表包含的单词也在 word2 列表的同义词集中
word2 列表包含的单词也在 word1 列表的同义词集中

如果单词在同义词集中，它们 return True

这是我的代码：

from nltk.corpus import wordnet as wn

word1 =  ['study', 'car']
word2 =  ['learn', 'motor']

def getSynonyms(word1):
    synonymList1 = []
    for data1 in word1:
        wordnetSynset1 = wn.synsets(data1)
        tempList1=[]
        for synset1 in wordnetSynset1:
            synLemmas = synset1.lemma_names()
            for i in xrange(len(synLemmas)):
                word = synLemmas[i].replace('_',' ')
                if word not in tempList1:
                    tempList1.append(word)
        synonymList1.append(tempList1)
    return synonymList1


def checkSynonyms(word1, word2):
    for i in xrange(len(word1)):
        for j in xrange(len(word2)):
            d1 = getSynonyms(word1)
            d2 = getSynonyms(word2)
            if word1[i] in d2:
                return True
            elif word2[j] in d1:
                return True
            else:
                return False

print word1
print
print word2
print
print getSynonyms(word1)
print
print getSynonyms(word2)
print 
print checkSynonyms(word1, word2)
print

但这是输出：

['study', 'car']

['learn', 'motor']

[[u'survey', u'study', u'work', u'report', u'written report', u'discipline', 
u'subject', u'subject area', u'subject field', u'field', u'field of study', 
u'bailiwick', u'sketch', u'cogitation', u'analyze', u'analyse', u'examine', 
u'canvass', u'canvas', u'consider', u'learn', u'read', u'take', u'hit the 
books', u'meditate', u'contemplate'], [u'car', u'auto', u'automobile', 
u'machine', u'motorcar', u'railcar', u'railway car', u'railroad car', 
u'gondola', u'elevator car', u'cable car']]

[[u'learn', u'larn', u'acquire', u'hear', u'get word', u'get wind', u'pick 
up', u'find out', u'get a line', u'discover', u'see', u'memorize', 
u'memorise', u'con', u'study', u'read', u'take', u'teach', u'instruct', 
u'determine', u'check', u'ascertain', u'watch'], [u'motor', u'drive', 
u'centrifugal', u'motive']]

False

正如我们所见，word1 中的单词 'study' 也在 word2 的同义词集中 >> u'study'

为什么 return 是假的？

Answer 1

因为你想比较word1和d2的字符串值，不要使用if word1[i] in d2:因为它会比较word1的字符串值和d2的数组值，例如它会比较：

'study' == [u'survey', u'study', u'work', u'report', u'written report', u'discipline', 
u'subject', u'subject area', u'subject field', u'field', u'field of study', 
u'bailiwick', u'sketch', u'cogitation', u'analyze', u'analyse', u'examine', 
u'canvass', u'canvas', u'consider', u'learn', u'read', u'take', u'hit the 
books', u'meditate', u'contemplate']

绝对会returnFalse

因此，不应使用 if word1[i] in d2:，而应使用 if word1[i] in d2[k]:，其中 k 是迭代器。

希望对您有所帮助。

如何检查单词是否在同义词集中？

How to check if words are in synsets or not?

python

words

list

synonym

nltk