查询将主要 table 与外部 table 和前 3 条记录作为来自外部 table 的列的 html

Query joining primary table with foreign table and the top 3 records as a html from a column of the foreign table

我有两个 Table:Category & Articles

类别Table:

CID |  CategoryName 
----+--------------
1   |  AAA Catg
2   |  BBB Catg
3   |  CCC Catg
4   |  DDD Catg
5   |  EEE Catg
6   |  FFF Catg

文章 Table:

AID | CID | ArticleTitle | ArticleURL      | Descrption      | Date
----+-----+--------------+-----------------+-----------------+-----------
1   | 1   | AA1 Title    | http://aa1.html | AA1 Description | 01-07-2017
2   | 1   | AA2 Title    | http://aa2.html | AA2 Description | 02-07-2017
3   | 1   | AA3 Title    | http://aa3.html | AA3 Description | 03-07-2017
4   | 1   | AA4 Title    | http://aa4.html | AA4 Description | 04-07-2017
5   | 1   | AA5 Title    | http://aa5.html | AA5 Description | 05-07-2017
6   | 2   | BB1 Title    | http://bb1.html | BB1 Description | 01-07-2017
7   | 2   | BB2 Title    | http://bb2.html | BB2 Description | 02-07-2017
8   | 2   | BB3 Title    | http://bb3.html | BB3 Description | 03-07-2017
9   | 3   | CC1 Title    | http://cc1.html | CC1 Description | 01-07-2017
10  | 3   | CC2 Title    | http://cc2.html | CC2 Description | 02-07-2017
11  | 4   | DD1 Title    | http://dd1.html | DD1 Description | 01-07-2017

我需要结果 table,方法是将类别 table 与文章 table 结合起来,通过获取文章 [=] 的前 3 条记录来生成一个列,该列将生成 html每个类别 63=]。
html 列应该是这样的:

<li>
    <a href="http://aa1.html">aa1 Title</a>
    <p>AA1 Description</p>
</li>
<li>
    <a href="http://aa2.html">AA2 Title</a>
</li>
<li>
    <a href="http://aa3.html">AA3 Title</a>
</li>

第一个 <li> 将在第一篇文章中包含锚标记和段落标记

<a href="http://aa1.html">aa1 Title</a>
<p>AA1 Description</p>

剩下的两个 <li> 标签将只有锚标签将是接下来的 2 篇文章

<a href="http://aa2.html">AA2 Title</a>

下面是结果table

CID | Category | HTML
----+----------+---------------------------------------------------------
1   | AAA Catg | <li><a href="http://aa1.html">AA1 Title</a><p>AA1 Description</p></li>
    |          | <li><a href="http://aa2.html">AA2 Title</a></li>
    |          | <li><a href="http://aa3.html">AA3 Title</a></li>

2   | BBB Catg | <li><a href="http://bb1.html">BB1 Title</a><p>BB1 Description</p></li>
    |          | <li><a href="http://bb2.html">BB2 Title</a></li>
    |          | <li><a href="http://bb3.html">BB3 Title</a></li>

3   | CCC Catg | <li><a href="http://cc1.html">CC1 Title</a><p>CC1 Description</p></li>
    |          | <li><a href="http://cc2.html">CC2 Title</a></li>

4   | DDD Catg | <li><a href="http://dd1.html">DD1 Title</a><p>DD1 Description</p></li>

5   | EEE Catg | 

6   | FFF Catg | 

这是我曾经使用过的查询

SELECT * FROM
(
    SELECT DISTINCT [CID]
    FROM [Articles]
) A
CROSS APPLY
(
    SELECT TOP 3 '<li><a href="' + B.[ArticleURL] + '">' + B.[ArticleTitle] + '</a><p>' + B.[Description] + '</p></li>'
    FROM [Articles] AS B 
    WHERE A.[CID] = B.[CID]
    FOR XML PATH('')
) C (ArticleList)

以上查询将在所有 li 个标签中生成 html 和段落

<li>
    <a href="http://aa1.html">aa1 Title</a>
    <p>AA1 Description</p>
</li>
<li>
    <a href="http://aa2.html">AA2 Title</a>
    <p>AA2 Description</p>
</li>
<li>
    <a href="http://aa3.html">AA3 Title</a>
    <p>AA3 Description</p>
</li>

但我只需要第一个 li 标签内的段落标签,而不是全部 3 个。 html 标签也将采用

的形式
&lt; li&gt;
        &lt; a href="http://aa3.html"&gt;AA3 Title&lt; /a&gt;
        &lt; p&gt;AA3 Description&lt; /p&gt;
&lt;/li&gt;

如何获取html格式?

尝试下面的查询

 ;with testdata as (
   select Articles.CID, CategoryName, ArticleTitle , ArticleURL,Description,Date
   ,row_number() over(partition by Category.CID order by AID) as rowNumber
   from Category inner join Articles on Category.CID= Articles.CID
 )
select 
  case when rowNumber=1 then '<li>' else '' End + '<a href="' 
  + [ArticleURL] + '">' + [ArticleTitle] + '</a><p>' + [Description] 
  + '</p>' +  case when rowNumber=3 then '</li>' else '' End 
from testdata where rowNumber<=3
for xml path('') ;

EDIT2 使用“对于 XML”

select CategoryName as '@id', (SELECT top 3
        ArticleURL as '@href'
       , ArticleTITLE   as'p'
    FROM
        Articles sub
    WHERE
        sub.CID= Category.CID
    order by sub.AID
    FOR 
        XML path('a'), 
        type
 )
   
 from Category 

for XML path('li')

我想你可以使用这个查询:

;with t as (
    select 
        *, 
        row_number() over (partition by CID order by AID) seq
    --  ^ this field will help us to find first Article of each Category
    from
        Articles
)
select 
    *,
    replace(replace(    -- I use `replace` for changing `<`, `>` to `&lt;`, ``&gt;`. `
    (select top 3
        ArticleURL "a/@href",
     --             ^ with using this column naming you will have a tag of `a` with attribute `href`. 
        case when seq = 1 then ArticleTitle end p
     from t
     where Category.CID = t.CID
     for xml path ('li')
     ) , '<', '&lt;'), '>', '&gt;') HTML
from 
    Category;

[ SQL Fiddle Demo ]
[ SQL Fiddle Demo - original tags ]