Selenium Python 在几页上查找元素

Selenium Python find element on few pages

在我的应用程序中,我有一个 table 用户。在我的测试中,我想添加新用户,然后检查是否添加了用户,但 table 可以有多个页面,当我查看该元素时,我只能在第一页上找到它。 这是我的代码:

def test_new_user(driver, username='jared144'):
login(driver, username="Admin", password="Password")
# add new user
add_new_user(driver, username)
#check if the new user added
assert is_element_present(driver, By.LINK_TEXT, "%s" % username)

def add_new_user(driver, username):
driver.find_element_by_css_selector("[id=btnAdd]").click()
driver.find_element_by_css_selector("[id=systemUser_employeeName_empName]").send_keys("Adelia Foxy")
driver.find_element_by_css_selector("[id=systemUser_userName]").send_keys("%s" % username)
driver.find_element_by_css_selector("[id=systemUser_password]").send_keys("12345678")
driver.find_element_by_css_selector("[id=systemUser_confirmPassword]").send_keys("12345678")
driver.find_element_by_css_selector("[id=btnSave]").click()

def is_element_present(driver, how, what):
try:
    driver.find_element(by=how, value=what)
except NoSuchElementException as e:
    return False
return True

def login(driver, username, password):
driver.get("http://hrm.seleniumminutes.com/")
driver.find_element_by_css_selector("[name=txtUsername]").send_keys(username)
driver.find_element_by_css_selector("[name=txtPassword]").send_keys(password)
driver.find_element_by_css_selector("[name=Submit]").click()
driver.find_element_by_css_selector("[id=menu_admin_viewAdminModule]").click()

我知道怎么做了,比如:

if NoSuchElementException
   find_element_by().click() #click second page

但是我不知道怎么实现

在你的例外情况下,告诉程序点击 next page 元素(你没有说明你是如何找到它的)。如果您的问题是如何找到单击时将带您进入下一页的元素,请打开 Chrome 或 FF 并按 F12 键调出调试器,然后在页面,获取其 ID、NAME、XPATH(或其他唯一标识符),然后在显示时单击它。所以这样的事情可能会奏效。

def is_element_present(driver, how, what):
    try:
        driver.find_element(by=how, value=what)
        return True
    except NoSuchElementException as e:
        try:
            driver.find_element(by=`xpath`, value=`next page xpath`).click()
            return True
        except NoSuchElementException as nse:
            return False