如何为 python 列表中的每个字符串创建子列表？

Question

例如，我有这个列表：

word1 =  ['organization', 'community']

我有一个函数可以从列表中的单词中获取同义词：

from nltk.corpus import wordnet as wn


def getSynonyms(word1):
    synonymList1 = []
    for data1 in word1:
        wordnetSynset1 = wn.synsets(data1)
        tempList1 = []
        for synset1 in wordnetSynset1:
            synLemmas = synset1.lemma_names()
            for s in synLemmas:
                word = s.replace('_', ' ')
                if word not in tempList1:
                    tempList1.append(word)
        synonymList1.append(tempList1)
    return synonymList1


syn1 = getSynonyms(word1)
print(syn1)

这是输出：

[
    ['organization', 'organisation', 'arrangement', 'system', 'administration',
     'governance', 'governing body', 'establishment', 'brass', 'constitution',
     'formation'],
    ['community', 'community of interests', 'residential district',
     'residential area', 'biotic community']
]

^ 上面的输出显示 'organization' 和 'community' 的每个同义词集都列在列表中。然后我降低列表的级别：

newlist1 = [val for sublist in syn1 for val in sublist]

这是输出：

['organization', 'organisation', 'arrangement', 'system', 'administration',
 'governance', 'governing body', 'establishment', 'brass', 'constitution',
 'formation', 'community', 'community of interests', 'residential district',
 'residential area', 'biotic community']

^ 现在所有同义词集都保持相同的字符串，没有子列表。而我现在要做的是让 newlist1 中的所有同义词集相互子列表。我希望输出是这样的：

[['organization'], ['organisation'], ['arrangement'], ['system'],
 ['administration'], ['governance'], ['governing body'], ['establishment'],
 ['brass'], ['constitution'], ['formation'], ['community'],
 ['community of interests'], ['residential district'], ['residential area'],
 ['biotic community']]

我正在尝试这段代码：

uplist1 = [[] for x in syn1]
uplist1.extend(syn1)
print(uplist1)

但结果不是我所期望的：

[[], [],
 ['organization', 'organisation', 'arrangement', 'system', 'administration',
  'governance', 'governing body', 'establishment', 'brass', 'constitution',
  'formation'],
 ['community', 'community of interests', 'residential district',
  'residential area', 'biotic community']]

它显示了 'organization' 和 'community'

的两个空列表和两个同义词集列表

如何将同义词集的每个字符串都变成一个子列表？

Answer 1

取出 syn1 中的每个元素并包裹在 [] 中使其成为子列表。

与append:

uplist1 = []
for i in syn1:
    uplist1.append([i])

或等效于列表理解：

uplist1 = [[i] for i in syn1]

Answer 2

感谢Meow's 给了我灵感。我想到了这个：

upuplist1 = []
for i in newlist1:
    upuplist1.append([i])

print(upuplist1)

这是我预期的输出：

[[u'organization'], [u'organisation'], [u'arrangement'], [u'system'], [u'administration'], [u'governance'], [u'governing body'], [u'establishment'], [u'brass'], [u'constitution'], [u'formation'], [u'community'], [u'community of interests'], [u'residential district'], [u'residential area'], [u'biotic community']]

Answer 3

您需要在列表理解中添加括号 [] 到 val，以便在创建 newlist1 时将每个 string 放入 list，因为示例：

newlist1 = [[val] for sublist in syn1 for val in sublist]

Answer 4

只需使用列表理解并将每个项目包装在列表中：

>>> lst = [[el] for el in newlist1]
[['organization'],
 ['organisation'],
 ['arrangement'],
 ['system'],
 ['administration'],
 ['governance'],
 ['governing body'],
 ['establishment'],
 ['brass'],
 ['constitution'],
 ['formation'],
 ['community'],
 ['community of interests'],
 ['residential district'],
 ['residential area'],
 ['biotic community']]

如何为 python 列表中的每个字符串创建子列表？

How to make a sublists for each strings inside a list in python?

python

string

list

sublist