最短的"time ago"
The shortest "time ago"
我创建了一个函数,它非常好地比较两个日期和 return 字符串的差异
extension Date {
var shortTimeAgo: String {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.year,.month,.weekOfMonth,.day,.hour,.minute,.second]
formatter.maximumUnitCount = 1
formatter.unitsStyle = .short
return formatter.string(from: self, to: Date())
}
}
但它 return 的值类似于“35 秒”、“10 分钟”甚至“2 天 1 小时”
如何获得更短的值,如“35s”、“10m”和“2d”?
试试这个代码 -
extension Date {
var shortTimeAgo: String {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.year,.month,.weekOfMonth,.day,.hour,.minute,.second]
formatter.maximumUnitCount = 1
formatter.unitsStyle = .abbreviated
return formatter.string(from: self, to: Date())
}
}
希望对您有所帮助!
我创建了一个函数,它非常好地比较两个日期和 return 字符串的差异
extension Date {
var shortTimeAgo: String {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.year,.month,.weekOfMonth,.day,.hour,.minute,.second]
formatter.maximumUnitCount = 1
formatter.unitsStyle = .short
return formatter.string(from: self, to: Date())
}
}
但它 return 的值类似于“35 秒”、“10 分钟”甚至“2 天 1 小时”
如何获得更短的值,如“35s”、“10m”和“2d”?
试试这个代码 -
extension Date {
var shortTimeAgo: String {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.year,.month,.weekOfMonth,.day,.hour,.minute,.second]
formatter.maximumUnitCount = 1
formatter.unitsStyle = .abbreviated
return formatter.string(from: self, to: Date())
}
}
希望对您有所帮助!