重新排列许多txt文件的结构，然后将它们合并到一个数据框中
Rearranging the structure of many txt files and then merging them in one data frame
非常感谢你的帮助！
我有 ~4.5k txt 文件，如下所示：
Simple statistics using MSPA parameters: 8_3_1_1 on input file: 20130815 104359 875 000000 0528 0548_result.tif
MSPA-class [color]: Foreground/data pixels [%] Frequency
============================================================
CORE(s) [green]: -- 0
CORE(m) [green]: 48.43/13.45 1
CORE(l) [green]: -- 0
ISLET [brown]: 3.70/ 1.03 20
PERFORATION [blue]: 0.00/ 0.00 0
EDGE [black]: 30.93/ 8.59 11
LOOP [yellow]: 9.66/ 2.68 6
BRIDGE [red]: 0.00/ 0.00 0
BRANCH [orange]: 7.28/ 2.02 40
Background [grey]: --- /72.22 11
Missing [white]: 0.00 0
我想将目录中的所有 txt 文件读入 R，然后在将它们合并之前对它们执行重新排列任务。
txt 文件中的值可以更改，因此在现在有 0.00 的地方，可能是某些文件中的相关数字（因此我们需要这些）。对于有 -- 现在的字段，如果脚本可以测试是否有 -- 或数字，那就太好了。如果有 --，那么它应该将它们变成 NA。另一方面，真正的 0.00 值是有价值的，我需要它们。 Missing white column (or row here) 只有一个值，然后应该将该值复制到两列中，foreground% 和 data pixels%。
我需要的一般重新排列是将所有数据作为列提供，每个 txt 文件只有 1 行。对于这里 txt 文件中的每一行数据，输出文件中应该有 3 列（前景、数据像素百分比和每种颜色的频率）。该行的名称应该是文件开头提到的图像名称，这里：20130815 104359 875 000000 0528 0548
其余可省略
输出应如下所示：
我正在同时进行此工作，但不确定该朝哪个方向发展。因此，我们非常欢迎任何帮助！
最好的，
莫里茨
我将您的数据复制并粘贴到一个文本文件中，并调整了 space 以使它们之间保持一致。您可能想要这样做，或者如果您可以附加一个文本文件，那么使用它会很容易。您可以使用 pastebin - http://en.wikipedia.org/wiki/Pastebin
首先设置你的工作目录如下：
setwd("path of your file")
#EDIT：创建所有文件的单个数据框
split.row.data <- function(x){
a1 = sub("( )+(.*)", '\2', x)
b1 = unlist(strsplit(sub("( )+(.*)", '\2', (strsplit(a1, ":"))[[1]][2]), " "))
c1 = unlist(strsplit(b1[1], "/"))
if(length(c1) == 1){
if(which(b1[1:2] %in% "") == 1){
c1 = c(NA, c1)
}else if(which(b1[1:2] %in% "") == 2){
c1 = c(c1, NA)
}
}
c1[which(c1 %in% c("--", "--- "))] <- NA
return(c(unlist(strsplit(strsplit(a1, ":")[[1]][1], " ")),
c1,
b1[length(b1)]))
}
df2 <- data.frame(matrix(nrow = 1, ncol = 6), stringsAsFactors = FALSE)
file_list = list.files('~/desktop', pattern = '^image\d+.txt', full.names = TRUE)
for (infile in file_list){
file_data <- readLines(con <- file(infile))
close(con)
filename = sub("(.*)(input file:)(.*)(.tif)", "\3", file_data[3])
a2 <- file_data[7:length(file_data)]
d1 = lapply(a2, function(x) split.row.data(x))
df1 <- data.frame(matrix(nrow= length(d1), ncol = 5), stringsAsFactors = FALSE)
for(i in 1:length(d1)){df1[i, ] <- d1[[i]]}
df1 <- cbind(data.frame(rep(filename, nrow(df1)), stringsAsFactors = FALSE),
df1)
colnames(df1) <- colnames(df2)
df2 <- rbind(df2, df1)
}
df2 <- df2[2:nrow(df2), ]
df2[,4] <- as.numeric(df2[,4])
df2[,5] <- as.numeric(df2[,5])
df2[,6] <- as.numeric(df2[,6])
e1 = unlist(lapply(df2[,3], function(x) gsub(']', '', x)))
df2[,3] = unlist(lapply(e1, function(x) gsub("[[]", '', x)))
header_names <- unlist(lapply(strsplit(file_data[5], "/"), function(x) strsplit(x, " ")))
colnames(df2) <- c("filename",
strsplit(header_names[1], " ")[[1]][2],
"color",
header_names[2:length(header_names)])
row.names(df2) <- 1:nrow(df2)
输出：
print(head(df2))
filename MSPA-class color Foreground data pixels [%] Frequency
1 20130815 103739 599 000000 0944 0788 CORE(s) green NA NA 0
2 20130815 103739 599 000000 0944 0788 CORE(m) green 63.46 17.41 1
3 20130815 103739 599 000000 0944 0788 CORE(l) green NA NA 0
4 20130815 103739 599 000000 0944 0788 ISLET brown 0.00 0.00 0
5 20130815 103739 599 000000 0944 0788 PERFORATION blue 0.00 0.00 0
6 20130815 103739 599 000000 0944 0788 EDGE black 35.00 9.60 1
#从 "MSPA-class" 列中仅获取 "background" 的数据
df2_background <- df2[which(df2[, "MSPA-class"] %in% "Background"), ]
print(df2_background)
filename MSPA-class color Foreground data pixels [%] Frequency
11 20130815 103739 599 000000 0944 0788 Background grey NA 72.57 1
22 20130815 143233 712 000000 1048 0520 Background grey NA 77.51 1
33 20130902 163929 019 000000 0394 0290 Background grey NA 54.55 6
我认为这是您想要的格式，但是示例与您的图片不匹配，所以我不能确定：
(lf <- list.files('~/desktop', pattern = '^image\d+.txt', full.names = TRUE))
# [1] "/Users/rawr/desktop/image001.txt" "/Users/rawr/desktop/image002.txt"
# [3] "/Users/rawr/desktop/image003.txt"
lapply(lf, function(xx) {
rl <- readLines(con <- file(xx), warn = FALSE)
close(con)
## assuming the file name is after "file: " until the end of the string
## and ends in .tif
img_name <- gsub('.*file:\s+(.*).tif', '\1', rl[1])
## removes each string up to and including the ===== string
rl <- rl[-(1:grep('==', rl))]
## remove leading whitespace
rl <- gsub('^\s+', '', rl)
## split the remaining lines by larger chunks of whitespace
mat <- do.call('rbind', strsplit(rl, '\s{2, }'))
## more cleaning, setting attributes, etc
mat[mat == '--'] <- NA
mat <- cbind(image_name = img_name, `colnames<-`(t(mat[, 2]), mat[, 1]))
as.data.frame(mat)
})
我使用您的示例创建了三个文件，并使每个文件都略有不同，以显示它如何在包含多个文件的目录上工作：
# [[1]]
# image_name CORE(s) [green]: CORE(m) [green]: CORE(l) [green]: ISLET [brown]: PERFORATION [blue]: EDGE [black]: LOOP [yellow]: BRIDGE [red]: BRANCH [orange]: Background [grey]: Missing [white]:
# 1 20130815 104359 875 000000 0528 0548_result <NA> 48.43/13.45 <NA> 3.70/ 1.03 0.00/ 0.00 30.93/ 8.59 9.66/ 2.68 0.00/ 0.00 7.28/ 2.02 --- /72.22 0.00
#
# [[2]]
# image_name CORE(s) [green]: CORE(m) [green]: CORE(l) [green]: ISLET [brown]: PERFORATION [blue]: EDGE [black]: LOOP [yellow]: BRIDGE [red]: BRANCH [orange]: Background [grey]: Missing [white]:
# 1 20139341 104359 875 000000 0528 0548_result 23 48.43/13.45 23 <NA> 0.00/ 0.00 30.93/ 8.59 9.66/ 2.68 0.00/ 0.00 7.28/ 2.02 --- /72.22 0.00
#
# [[3]]
# image_name CORE(s) [green]: CORE(m) [green]: CORE(l) [green]: ISLET [brown]: PERFORATION [blue]: EDGE [black]: LOOP [yellow]: BRIDGE [red]: BRANCH [orange]: Background [grey]: Missing [white]:
# 1 20132343 104359 875 000000 0528 0548_result <NA> <NA> <NA> <NA> <NA> 30.93/ 8.59 9.66/ 2.68 0.00/ 0.00 7.28/ 2.02 <NA> 0.00
编辑
进行了一些更改以提取所有信息：
(lf <- list.files('~/desktop', pattern = '^image\d+.txt', full.names = TRUE))
# [1] "/Users/rawr/desktop/image001.txt" "/Users/rawr/desktop/image002.txt"
# [3] "/Users/rawr/desktop/image003.txt"
res <- lapply(lf, function(xx) {
rl <- readLines(con <- file(xx), warn = FALSE)
close(con)
img_name <- gsub('.*file:\s+(.*).tif', '\1', rl[1])
rl <- rl[-(1:grep('==', rl))]
rl <- gsub('^\s+', '', rl)
mat <- do.call('rbind', strsplit(rl, '\s{2, }'))
dat <- as.data.frame(mat, stringsAsFactors = FALSE)
tmp <- `colnames<-`(do.call('rbind', strsplit(dat$V2, '[-\/\s]+', perl = TRUE)),
c('Foreground','Data pixels'))
dat <- cbind(dat[, -2], tmp, image_name = img_name)
dat[] <- lapply(dat, as.character)
dat[dat == ''] <- NA
names(dat)[1:2] <- c('MSPA-class','Frequency')
zzz <- reshape(dat, direction = 'wide', idvar = 'image_name', timevar = 'MSPA-class')
names(zzz)[-1] <- gsub('(.*)\.(.*) (?:.*)', '\2_\1', names(zzz)[-1], perl = TRUE)
zzz
})
这是结果（我只是转换成一个长矩阵，这样会更容易阅读。真正的结果是在一个非常宽的数据框中，每个文件一个）：
`rownames<-`(matrix(res[[1]]), names(res[[1]]))
# [,1]
# image_name "20130815 104359 875 000000 0528 0548_result"
# CORE(s)_Frequency "0"
# CORE(s)_Foreground "NA"
# CORE(s)_Data pixels "NA"
# CORE(m)_Frequency "1"
# CORE(m)_Foreground "48.43"
# CORE(m)_Data pixels "13.45"
# CORE(l)_Frequency "0"
# CORE(l)_Foreground "NA"
# CORE(l)_Data pixels "NA"
# ISLET_Frequency "20"
# ISLET_Foreground "3.70"
# ISLET_Data pixels "1.03"
# PERFORATION_Frequency "0"
# PERFORATION_Foreground "0.00"
# PERFORATION_Data pixels "0.00"
# EDGE_Frequency "11"
# EDGE_Foreground "30.93"
# EDGE_Data pixels "8.59"
# LOOP_Frequency "6"
# LOOP_Foreground "9.66"
# LOOP_Data pixels "2.68"
# BRIDGE_Frequency "0"
# BRIDGE_Foreground "0.00"
# BRIDGE_Data pixels "0.00"
# BRANCH_Frequency "40"
# BRANCH_Foreground "7.28"
# BRANCH_Data pixels "2.02"
# Background_Frequency "11"
# Background_Foreground "NA"
# Background_Data pixels "72.22"
# Missing_Frequency "0"
# Missing_Foreground "0.00"
# Missing_Data pixels "0.00"
使用您的示例数据：
lf <- list.files('~/desktop/data', pattern = '.txt', full.names = TRUE)
`rownames<-`(matrix(res[[1]]), names(res[[1]]))
# [,1]
# image_name "20130815 103704 780 000000 0372 0616"
# CORE(s)_Frequency "0"
# CORE(s)_Foreground "NA"
# CORE(s)_Data pixels "NA"
# CORE(m)_Frequency "1"
# CORE(m)_Foreground "54.18"
# CORE(m)_Data pixels "15.16"
# CORE(l)_Frequency "0"
# CORE(l)_Foreground "NA"
# CORE(l)_Data pixels "NA"
# ISLET_Frequency "11"
# ISLET_Foreground "3.14"
# ISLET_Data pixels "0.88"
# PERFORATION_Frequency "0"
# PERFORATION_Foreground "0.00"
# PERFORATION_Data pixels "0.00"
# EDGE_Frequency "1"
# EDGE_Foreground "34.82"
# EDGE_Data pixels "9.75"
# LOOP_Frequency "1"
# LOOP_Foreground "4.96"
# LOOP_Data pixels "1.39"
# BRIDGE_Frequency "0"
# BRIDGE_Foreground "0.00"
# BRIDGE_Data pixels "0.00"
# BRANCH_Frequency "20"
# BRANCH_Foreground "2.89"
# BRANCH_Data pixels "0.81"
# Background_Frequency "1"
# Background_Foreground "NA"
# Background_Data pixels "72.01"
# Missing_Frequency "0"
# Missing_Foreground "0.00"
# Missing_Data pixels "0.00"
非常感谢你的帮助！
我有 ~4.5k txt 文件，如下所示：
Simple statistics using MSPA parameters: 8_3_1_1 on input file: 20130815 104359 875 000000 0528 0548_result.tif
MSPA-class [color]: Foreground/data pixels [%] Frequency
============================================================
CORE(s) [green]: -- 0
CORE(m) [green]: 48.43/13.45 1
CORE(l) [green]: -- 0
ISLET [brown]: 3.70/ 1.03 20
PERFORATION [blue]: 0.00/ 0.00 0
EDGE [black]: 30.93/ 8.59 11
LOOP [yellow]: 9.66/ 2.68 6
BRIDGE [red]: 0.00/ 0.00 0
BRANCH [orange]: 7.28/ 2.02 40
Background [grey]: --- /72.22 11
Missing [white]: 0.00 0
我想将目录中的所有 txt 文件读入 R，然后在将它们合并之前对它们执行重新排列任务。
txt 文件中的值可以更改，因此在现在有 0.00 的地方，可能是某些文件中的相关数字（因此我们需要这些）。对于有 -- 现在的字段，如果脚本可以测试是否有 -- 或数字，那就太好了。如果有 --，那么它应该将它们变成 NA。另一方面，真正的 0.00 值是有价值的，我需要它们。 Missing white column (or row here) 只有一个值，然后应该将该值复制到两列中，foreground% 和 data pixels%。
我需要的一般重新排列是将所有数据作为列提供，每个 txt 文件只有 1 行。对于这里 txt 文件中的每一行数据，输出文件中应该有 3 列（前景、数据像素百分比和每种颜色的频率）。该行的名称应该是文件开头提到的图像名称，这里：20130815 104359 875 000000 0528 0548
其余可省略
输出应如下所示：
我正在同时进行此工作，但不确定该朝哪个方向发展。因此，我们非常欢迎任何帮助！
最好的， 莫里茨
我将您的数据复制并粘贴到一个文本文件中，并调整了 space 以使它们之间保持一致。您可能想要这样做，或者如果您可以附加一个文本文件，那么使用它会很容易。您可以使用 pastebin - http://en.wikipedia.org/wiki/Pastebin
首先设置你的工作目录如下：
setwd("path of your file")
#EDIT：创建所有文件的单个数据框
split.row.data <- function(x){
a1 = sub("( )+(.*)", '\2', x)
b1 = unlist(strsplit(sub("( )+(.*)", '\2', (strsplit(a1, ":"))[[1]][2]), " "))
c1 = unlist(strsplit(b1[1], "/"))
if(length(c1) == 1){
if(which(b1[1:2] %in% "") == 1){
c1 = c(NA, c1)
}else if(which(b1[1:2] %in% "") == 2){
c1 = c(c1, NA)
}
}
c1[which(c1 %in% c("--", "--- "))] <- NA
return(c(unlist(strsplit(strsplit(a1, ":")[[1]][1], " ")),
c1,
b1[length(b1)]))
}
df2 <- data.frame(matrix(nrow = 1, ncol = 6), stringsAsFactors = FALSE)
file_list = list.files('~/desktop', pattern = '^image\d+.txt', full.names = TRUE)
for (infile in file_list){
file_data <- readLines(con <- file(infile))
close(con)
filename = sub("(.*)(input file:)(.*)(.tif)", "\3", file_data[3])
a2 <- file_data[7:length(file_data)]
d1 = lapply(a2, function(x) split.row.data(x))
df1 <- data.frame(matrix(nrow= length(d1), ncol = 5), stringsAsFactors = FALSE)
for(i in 1:length(d1)){df1[i, ] <- d1[[i]]}
df1 <- cbind(data.frame(rep(filename, nrow(df1)), stringsAsFactors = FALSE),
df1)
colnames(df1) <- colnames(df2)
df2 <- rbind(df2, df1)
}
df2 <- df2[2:nrow(df2), ]
df2[,4] <- as.numeric(df2[,4])
df2[,5] <- as.numeric(df2[,5])
df2[,6] <- as.numeric(df2[,6])
e1 = unlist(lapply(df2[,3], function(x) gsub(']', '', x)))
df2[,3] = unlist(lapply(e1, function(x) gsub("[[]", '', x)))
header_names <- unlist(lapply(strsplit(file_data[5], "/"), function(x) strsplit(x, " ")))
colnames(df2) <- c("filename",
strsplit(header_names[1], " ")[[1]][2],
"color",
header_names[2:length(header_names)])
row.names(df2) <- 1:nrow(df2)
输出：
print(head(df2))
filename MSPA-class color Foreground data pixels [%] Frequency
1 20130815 103739 599 000000 0944 0788 CORE(s) green NA NA 0
2 20130815 103739 599 000000 0944 0788 CORE(m) green 63.46 17.41 1
3 20130815 103739 599 000000 0944 0788 CORE(l) green NA NA 0
4 20130815 103739 599 000000 0944 0788 ISLET brown 0.00 0.00 0
5 20130815 103739 599 000000 0944 0788 PERFORATION blue 0.00 0.00 0
6 20130815 103739 599 000000 0944 0788 EDGE black 35.00 9.60 1
#从 "MSPA-class" 列中仅获取 "background" 的数据
df2_background <- df2[which(df2[, "MSPA-class"] %in% "Background"), ]
print(df2_background)
filename MSPA-class color Foreground data pixels [%] Frequency
11 20130815 103739 599 000000 0944 0788 Background grey NA 72.57 1
22 20130815 143233 712 000000 1048 0520 Background grey NA 77.51 1
33 20130902 163929 019 000000 0394 0290 Background grey NA 54.55 6
我认为这是您想要的格式，但是示例与您的图片不匹配，所以我不能确定：
(lf <- list.files('~/desktop', pattern = '^image\d+.txt', full.names = TRUE))
# [1] "/Users/rawr/desktop/image001.txt" "/Users/rawr/desktop/image002.txt"
# [3] "/Users/rawr/desktop/image003.txt"
lapply(lf, function(xx) {
rl <- readLines(con <- file(xx), warn = FALSE)
close(con)
## assuming the file name is after "file: " until the end of the string
## and ends in .tif
img_name <- gsub('.*file:\s+(.*).tif', '\1', rl[1])
## removes each string up to and including the ===== string
rl <- rl[-(1:grep('==', rl))]
## remove leading whitespace
rl <- gsub('^\s+', '', rl)
## split the remaining lines by larger chunks of whitespace
mat <- do.call('rbind', strsplit(rl, '\s{2, }'))
## more cleaning, setting attributes, etc
mat[mat == '--'] <- NA
mat <- cbind(image_name = img_name, `colnames<-`(t(mat[, 2]), mat[, 1]))
as.data.frame(mat)
})
我使用您的示例创建了三个文件，并使每个文件都略有不同，以显示它如何在包含多个文件的目录上工作：
# [[1]]
# image_name CORE(s) [green]: CORE(m) [green]: CORE(l) [green]: ISLET [brown]: PERFORATION [blue]: EDGE [black]: LOOP [yellow]: BRIDGE [red]: BRANCH [orange]: Background [grey]: Missing [white]:
# 1 20130815 104359 875 000000 0528 0548_result <NA> 48.43/13.45 <NA> 3.70/ 1.03 0.00/ 0.00 30.93/ 8.59 9.66/ 2.68 0.00/ 0.00 7.28/ 2.02 --- /72.22 0.00
#
# [[2]]
# image_name CORE(s) [green]: CORE(m) [green]: CORE(l) [green]: ISLET [brown]: PERFORATION [blue]: EDGE [black]: LOOP [yellow]: BRIDGE [red]: BRANCH [orange]: Background [grey]: Missing [white]:
# 1 20139341 104359 875 000000 0528 0548_result 23 48.43/13.45 23 <NA> 0.00/ 0.00 30.93/ 8.59 9.66/ 2.68 0.00/ 0.00 7.28/ 2.02 --- /72.22 0.00
#
# [[3]]
# image_name CORE(s) [green]: CORE(m) [green]: CORE(l) [green]: ISLET [brown]: PERFORATION [blue]: EDGE [black]: LOOP [yellow]: BRIDGE [red]: BRANCH [orange]: Background [grey]: Missing [white]:
# 1 20132343 104359 875 000000 0528 0548_result <NA> <NA> <NA> <NA> <NA> 30.93/ 8.59 9.66/ 2.68 0.00/ 0.00 7.28/ 2.02 <NA> 0.00
编辑
进行了一些更改以提取所有信息：
(lf <- list.files('~/desktop', pattern = '^image\d+.txt', full.names = TRUE))
# [1] "/Users/rawr/desktop/image001.txt" "/Users/rawr/desktop/image002.txt"
# [3] "/Users/rawr/desktop/image003.txt"
res <- lapply(lf, function(xx) {
rl <- readLines(con <- file(xx), warn = FALSE)
close(con)
img_name <- gsub('.*file:\s+(.*).tif', '\1', rl[1])
rl <- rl[-(1:grep('==', rl))]
rl <- gsub('^\s+', '', rl)
mat <- do.call('rbind', strsplit(rl, '\s{2, }'))
dat <- as.data.frame(mat, stringsAsFactors = FALSE)
tmp <- `colnames<-`(do.call('rbind', strsplit(dat$V2, '[-\/\s]+', perl = TRUE)),
c('Foreground','Data pixels'))
dat <- cbind(dat[, -2], tmp, image_name = img_name)
dat[] <- lapply(dat, as.character)
dat[dat == ''] <- NA
names(dat)[1:2] <- c('MSPA-class','Frequency')
zzz <- reshape(dat, direction = 'wide', idvar = 'image_name', timevar = 'MSPA-class')
names(zzz)[-1] <- gsub('(.*)\.(.*) (?:.*)', '\2_\1', names(zzz)[-1], perl = TRUE)
zzz
})
这是结果（我只是转换成一个长矩阵，这样会更容易阅读。真正的结果是在一个非常宽的数据框中，每个文件一个）：
`rownames<-`(matrix(res[[1]]), names(res[[1]]))
# [,1]
# image_name "20130815 104359 875 000000 0528 0548_result"
# CORE(s)_Frequency "0"
# CORE(s)_Foreground "NA"
# CORE(s)_Data pixels "NA"
# CORE(m)_Frequency "1"
# CORE(m)_Foreground "48.43"
# CORE(m)_Data pixels "13.45"
# CORE(l)_Frequency "0"
# CORE(l)_Foreground "NA"
# CORE(l)_Data pixels "NA"
# ISLET_Frequency "20"
# ISLET_Foreground "3.70"
# ISLET_Data pixels "1.03"
# PERFORATION_Frequency "0"
# PERFORATION_Foreground "0.00"
# PERFORATION_Data pixels "0.00"
# EDGE_Frequency "11"
# EDGE_Foreground "30.93"
# EDGE_Data pixels "8.59"
# LOOP_Frequency "6"
# LOOP_Foreground "9.66"
# LOOP_Data pixels "2.68"
# BRIDGE_Frequency "0"
# BRIDGE_Foreground "0.00"
# BRIDGE_Data pixels "0.00"
# BRANCH_Frequency "40"
# BRANCH_Foreground "7.28"
# BRANCH_Data pixels "2.02"
# Background_Frequency "11"
# Background_Foreground "NA"
# Background_Data pixels "72.22"
# Missing_Frequency "0"
# Missing_Foreground "0.00"
# Missing_Data pixels "0.00"
使用您的示例数据：
lf <- list.files('~/desktop/data', pattern = '.txt', full.names = TRUE)
`rownames<-`(matrix(res[[1]]), names(res[[1]]))
# [,1]
# image_name "20130815 103704 780 000000 0372 0616"
# CORE(s)_Frequency "0"
# CORE(s)_Foreground "NA"
# CORE(s)_Data pixels "NA"
# CORE(m)_Frequency "1"
# CORE(m)_Foreground "54.18"
# CORE(m)_Data pixels "15.16"
# CORE(l)_Frequency "0"
# CORE(l)_Foreground "NA"
# CORE(l)_Data pixels "NA"
# ISLET_Frequency "11"
# ISLET_Foreground "3.14"
# ISLET_Data pixels "0.88"
# PERFORATION_Frequency "0"
# PERFORATION_Foreground "0.00"
# PERFORATION_Data pixels "0.00"
# EDGE_Frequency "1"
# EDGE_Foreground "34.82"
# EDGE_Data pixels "9.75"
# LOOP_Frequency "1"
# LOOP_Foreground "4.96"
# LOOP_Data pixels "1.39"
# BRIDGE_Frequency "0"
# BRIDGE_Foreground "0.00"
# BRIDGE_Data pixels "0.00"
# BRANCH_Frequency "20"
# BRANCH_Foreground "2.89"
# BRANCH_Data pixels "0.81"
# Background_Frequency "1"
# Background_Foreground "NA"
# Background_Data pixels "72.01"
# Missing_Frequency "0"
# Missing_Foreground "0.00"
# Missing_Data pixels "0.00"