Swift JSON 提取

Question

我正在开发 swift iOS 应用程序并从 Web 服务获得以下 JSON 响应。我正在尝试解析并从中获取 nextResponse 。我无法提取它。有人可以指导我解决这个问题吗？

listofstudents:
        ({
        studentsList =     (
                    {
                data =             (
                    "32872.23",
                    "38814.87",
                    "38915.85"
                );
                label = “name, parents and guardians”;
            }
        );
        dateList =     (
            "Apr 26, 2017",
            "Jun 10, 2017",
            "Jul 26, 2017"
        );
        firstResponse = “This school has 1432 students and 387 teachers.”;
        nextResponse = “This school has around 1400 students.”;
    })

Swift代码：

    do {
                let json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary
                print("json: \(json)")

                if let parseJSON = json {

                    let finalResponse = parseJSON["listofstudents"] as? AnyObject
                    print("listofstudents::   \(finalResponse)")

                    let nextResponse = parseJSON["nextResponse"] as? AnyObject
                    print("nextResponse::   \(nextResponse)")
         }
            } catch {
                print(error)
            }

Answer 1

nextResponse 是 JSON 结构的一部分（它是一个嵌套节点）。所以你应该使用以下方式访问它：

typealias JSON = [String: Any]
if let finalResponse = parseJSON["listofstudents"] as? JSON {
    let nextResponse = finalResponse ["nextResponse"] as? JSON
    print("nextResponse::   \(nextResponse)")
}

Answer 2

看起来你的 listofstudents 是一个字典数组，所以尝试迭代它并提取它：-

if let finalResponse = parseJSON["listofstudents"] as? [String: Any] {
 //If your finalResponse has list then you can print all the data
  for response in finalResponse {
    let nextResponse = finalResponse ["nextResponse"] as? AnyObject
    print("nextResponse::\(nextResponse)")
  }
}

Answer 3

不要在 Swift 中使用 NSDictionary，而是使用其原生的 Swift 对应物 Dictionary。这是您访问嵌入在其他词典中的词典的方式：

do {
    guard let json = try JSONSerialization.jsonObject(with: data!) as? [String:Any] else {return}
    print("json: \(json)")

    guard let finalResponse = parseJSON["listofstudents"] as? [String:Any] else {return}
    print("listofstudents::   \(finalResponse)")

    guard let nextResponse = finalResponse["nextResponse"] as? [String:Any] else {return}
    print("nextResponse::   \(nextResponse)")
} catch {
    print(error)
}

Swift JSON 提取

Swift JSON extraction

ios

swift

nsjsonserialization