如何将curl命令变成php？

Question

我有这个 curl 命令

curl -L -O -o ' .$path.' -J "https://drive.google.com/uc?export=download&id='.$id.'"

我如何将其转换为 php curl 请求，同时牢记所有标志。 php

中的等价物是什么

这是我目前所拥有的

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "https://drive.google.com/uc?export=download&id='.$id.'");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
$result = curl_exec($ch);
if (curl_errno($ch)) {
    echo 'Error:' . curl_error($ch);
}

Answer 1

$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, "https://drive.google.com/uc?export=download&id=123"]);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);

$result = curl_exec($ch);
if (curl_errno($ch)) {
    echo 'Error:' . curl_error($ch);
}
curl_close ($ch);

Answer 2

主要是缺少保存操作 (-o $path)：

<?php
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "https://drive.google.com/uc?export=download&id='.$id.'");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
$result = curl_exec($ch);
if (curl_errno($ch)) {
    echo 'Error:' . curl_error($ch);
}

file_put_contents($path, $result);
?>

如何将curl命令变成php？

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