在 hive/mysql 中实施 sum_reverse() [分解 table 结果]

Question

我们要平均分配数量。 Table 销量如下

product category qty
123     A        3
345     B        2

输出

product category qty
123     A        1
123     A        1
123     A        1
345     B        1
345     B        1

Answer 1

如果您有 table 个号码，您可以：

select s.product, s.category, 1 as qty
from sales s join
     numbers n
     on n.n <= s.qty and n.n > 0;

在MySQL中，您可以使用变量生成这样的table。例如，如果 sales 足够大：

select s.product, s.category, 1 as qty
from sales s join
     (select (@rn := @rn + 1) as n
      from sales s cross join
           (select @rn := 0) params
     ) n
     on n.n <= s.qty and n.n > 0;

Answer 2

我自己想出答案（这是在配置单元中）

select category,main1.product,main2.qty from (select category,product,
split(substring(repeat(concat(1,','),int(qty)),0,int(qty*2)-1),",") as qty from 
(select collect_set(product) product,category,
sum(qty) qty
from sales) main
lateral view explode(product) main1 as product
lateral view explode(qty) main2 AS qty;

Answer 3

蜂巢

select  t.product
       ,t.category
       ,1           as qty

from    mytable t
        lateral view explode(split(space(t.qty - 1),' ')) e
;

+---------+----------+-----+
| product | category | qty |
+---------+----------+-----+
| 123     | A        | 1   |
+---------+----------+-----+
| 123     | A        | 1   |
+---------+----------+-----+
| 123     | A        | 1   |
+---------+----------+-----+
| 345     | B        | 1   |
+---------+----------+-----+
| 345     | B        | 1   |
+---------+----------+-----+

在 hive/mysql 中实施 sum_reverse() [分解 table 结果]

Implement sum_reverse() [Explode table result] in either hive/mysql

mysql

sql

hive

explode

hiveql

蜂巢