获取加速度计输入 - Defold Engine

Question

我正在尝试使用加速度计移动角色。

但是在on_input()中使用action.acc_x/action.acc_y/action.acc_z，我只能在执行其他操作时才能获取信息（ "click"、"left"、"right")

我想将脚本更改为仅随着设备的移动来移动角色

function on_input(self, action_id, action)

    label.set_text("info#action", "action: ".. action_id)
    label.set_text("info#info", "info: ".. tostring(action.acc_x) ..", ".. tostring(action.acc_y) ..", "..tostring(action.acc_z))
    if action.acc_x > 0 then
        self.player_direction.x = 1
    elseif action.acc_x < 0 then
        self.player_direction.x = -1
    else
        self.player_direction.x = 0
    end
end

github: game.script

Answer 1

据我所知，当 action_id 为 nil 时，Defold 只有一种情况 - 即从加速度计接收到数据时。这意味着你可以写：

function on_input(self, action_id, action)
  if not action_id then
    label.set_text("info#action", "action: ".. tostring(action_id))
   label.set_text("info#info", "info: ".. tostring(action.acc_x) ..", ".. tostring(action.acc_y) ..", "..tostring(action.acc_z))
    if action.acc_x > 0 then
      self.player_direction.x = 1
    elseif action.acc_x < 0 then
      self.player_direction.x = -1
    else
      self.player_direction.x = 0
    end
  end
end

别忘了替换

label.set_text("info#action", "action: "..action_id)

和

label.set_text("info#action", "action: ".. tostring(action_id))

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