Perl 6 的 uncuddled else 是语句分离的特例吗？

Question

A closing curly brace followed by a newline character implies a statement separator, which is why you don't need to write a semicolon after an if statement block.

if True {
    say "Hello";
}
say "world";

很好，发生了什么。

但是，这条规则如何适用于未被拥抱的 else？这是特例吗？

if True {
    say "Hello";
}
else {
    say "Something else";
}
say "world";

或者 with-orwith example:

my $s = "abc";
with   $s.index("a") { say "Found a at $_" }
orwith $s.index("b") { say "Found b at $_" }
orwith $s.index("c") { say "Found c at $_" }
else                 { say "Didn't find a, b or c" }

Answer 1

您找到的文档不完全正确。 documentation has been updated and is now correct。现在显示为：

Complete statements ending in bare blocks can omit the trailing semicolon, if no additional statements on the same line follow the block's closing curly brace }.

...

For a series of blocks that are part of the same if/elsif/else (or similar) construct, the implied separator rule only applies at the end of the last block of that series.

原回答：

查看 nqp and Rakudo 中 if 的语法，似乎一组 if/elsif/else 块被一起解析为一个控制语句。

`if` 在 `nqp`

中的规则

rule statement_control:sym<if> {
    <sym>\s
    <xblock>
    [ 'elsif'\s <xblock> ]*
    [ 'else'\s <else=.pblock> ]?
}

(https://github.com/perl6/nqp/blob/master/src/NQP/Grammar.nqp#L243，截至 2017 年 8 月 5 日)

乐道 `if` 的规则

rule statement_control:sym<if> {
    $<sym>=[if|with]<.kok> {}
    <xblock(so ~$<sym>[0] ~~ /with/)>
    [
        [
        | 'else'\h*'if' <.typed_panic: 'X::Syntax::Malformed::Elsif'>
        | 'elif' { $/.typed_panic('X::Syntax::Malformed::Elsif', what => "elif") }
        | $<sym>='elsif' <xblock>
        | $<sym>='orwith' <xblock(1)>
        ]
    ]*
    {}
    [ 'else' <else=.pblock(so ~$<sym>[-1] ~~ /with/)> ]?
}

（https://github.com/rakudo/rakudo/blob/nom/src/Perl6/Grammar.nqp#L1450 截至 2017 年 8 月 5 日）

Perl 6 的 uncuddled else 是语句分离的特例吗？

Is Perl 6's uncuddled else a special case for statement separation?

raku

if 在 nqp

乐道 if 的规则

`if` 在 `nqp`

乐道 `if` 的规则