将列表中的数据排序为 xlsx 文件的列

Question

我有一个看起来像这样的列表。（数据来自几个xlsx文件）：

[['A B 10', 2, 'A B 10', 3, 1, AC], ['A B 104', 3, 'A B 104', 2, -1, 'AC']]
[['D B 126', 3, 'D B 126', 2, -1, 'EFG 1'], ['D B 15', 3, 'D B 15', 2, -1, 'EFG 1']
[]
[]
[['D B 544', 2, 'D B 544', 1, -1, 'EFG 11'], ['D B 152', 3, 'D B 152', 2, -1, 'EFG 11'], ['D B 682', 3, 'D B 682', 2, -1, 'EFG 11']

我想将此信息放入一个新的 xlsx 文件中，但首先我需要将数据按行和列排序。我希望每个子列表中的所有第一个字符串都添加到第一列，第二列中的数字等。所以这些列就是逗号所在的位置。我也不希望列表有子列表，所以所有内容都应该在同一个列表中。像这样：

['A B 10', 2, 'A B 10', 3, 1, AC, 
 'A B 104', 3, 'A B 104', 2, -1, 'AC'
 'D B 126', 3, 'D B 126', 2, -1, 'EFG 1'
 'D B 15', 3, 'D B 15', 2, -1, 'EFG 1'
 'D B 544', 2, 'D B 544', 1, -1, 'EFG 11'
 'D B 152', 3, 'D B 152', 2, -1, 'EFG 11' 
 'D B 682', 3, 'D B 682', 2, -1, 'EFG 11']

这是我在代码上的进展：

import pandas as pd
from openpyxl import Workbook, load_workbook
import glob
from openpyxl.utils.dataframe import dataframe_to_rows

numbers = []
os.chdir(r'C:Myfolder')
files = glob.glob('*.xlsx')
print(files)
for file in files: #Getting the data from xlsx files and to the numbers-list
    df = pd.read_excel(file)
    m = (df.iloc[:,4] - df.iloc[:,1]) != 0
    pos = [0,1,3,4,6,7]
    numbers = (df.loc[m, df.columns[pos]].values.tolist())
    print(numbers)
excel_input = load_workbook(rapp) #Going from using pandas and dataframes to working with openpyxl (Just because I am not that familiar with pandas).
ws = excel_input.active
for r in dataframe_to_rows(df, index=True, header=True):
    ws.append(r)
else:
    pass

col1 = [] #Creating open lists to put the data into columns
col2 = []
col4 = []
col5 = []
col7 = []
col8 = []

mainlist = []
try:
    for row in numbers: #Putting the data into the columns lists
        col1.append(ws.cell(row=row, column=1).value) #This is wrong, and is throwing the error
        col2.append(ws.cell(row=row, column=2).value) #Wrong
        col4.append(ws.cell(row=row, column=4).value) #Wrong
        col5.append(ws.cell(row=row, column=5).value) #Wrong
        col7.append(ws.cell(row=row, column=7).value) #Wrong
        col8.append(ws.cell(row=row, column=8).value) #Wrong
except AttributeError:
    logging.error('Something is wrong')
finally:
    columns = zip(col1, col2, col4, col5, col7, col8) #Zipping the lists
    for column in columns:
        mainlist.append(column)

Traceback: col1.append(ws.cell(row=row, column=1).value) File "C:\Python3\lib\site-packages\openpyxl\worksheet\worksheet.py", line 306, in cell if row < 1 or column < 1: TypeError: unorderable types: list() < int()

有谁知道如何在不出现错误的情况下执行此操作？错误的地方我已经在代码里评论了

编辑：

通过使用@stovfl 的方法，我能够将一些数据放入 xlsx 文件中，但是由于我的列表是列表的列表，所以只有最后一个列表被添加到我的 xlsx 文件中。我使用了这段代码：

from openpyxl import load_workbook

report = load_workbook(r"C:\Myworkbook.xlsx")
ws = report.create_sheet('My sheet')
for _list in numbers:
    for row_data in _list:
        ws.append([row_data])
        print(row_data)
report.save(r"C\Myworkbook.xlsx")

打印：

A B 10
2
A B 10
3
1
AC

xlsx 文件中的输出：

问题是只添加了最后一个列表，而不是整个列表列表，我希望输出看起来像这样：

Answer 1

我不知道我是否理解得很好，但是如果你有这样的列表：

l = [rows, rows, rows, ...]

为了创建数据框，您可以遍历列表 l 中的每个元素，例如：

df = pd.DataFrame()
for rows in l:
    for row in rows:
        df = pd.concat([df, row])

在你的例子中，它给了我以下输出：

    0       1   2       3   4   5
0   A B 10  2   A B 10  3   1   AC
1   A B 104 3   A B 104 2   -1  AC
0   D B 126 3   D B 126 2   -1  EFG 1
1   D B 15  3   D B 15  2   -1  EFG 1
0   D B 544 2   D B 544 1   -1  EFG 11
1   D B 152 3   D B 152 2   -1  EFG 11
2   D B 682 3   D B 682 2   -1  EFG 11

Answer 2

Question: ... only the last list was added to my xlsx file

第一个for loop是你的for file in files:.
我将下面的代码更新为此。

Question: how to do this without getting the error?

使用openpyxl编写列表列表的解决方案，例如

newWorkbook = False
newWorksheet = False

if newWorkbook:
    from openpyxl import Workbook
    wb = Workbook()
    # Select First Worksheet
    ws = wb.worksheets[0]
else:
    from openpyxl import load_workbook
    wb = load_workbook("mySortData.xlsx")
    if newWorksheet:
        # Create a New Worksheet in this Workbook
        ws = wb.create_chartsheet('Sheet 2')
    else:
        # Select a Worksheet by Name in this Workbook
        ws = wb['Sheet']

for file in files:  # Getting the data from xlsx files and to the numbers-list
    df = pd.read_excel(file)
    m = (df.iloc[:, 4] - df.iloc[:, 1]) != 0
    pos = [0, 1, 3, 4, 6, 7]
    numbers = (df.loc[m, df.columns[pos]].values.tolist())

    # numbers is a List[Row Data] of List[Columns]
    # Iterate List of Row Data
    for row_data in numbers:
        ws.append(row_data)

wb.save("mySortData.xlsx")

Output:

将列表列表直接写入 CSV 的解决方案，例如：

# Data == List of List
data = [[['A B 10', 2, 'A B 10', 3, 1, 'AC'], ['A B 104', 3, 'A B 104', 2, -1, 'AC']],
[['D B 126', 3, 'D B 126', 2, -1, 'EFG 1'], ['D B 15', 3, 'D B 15', 2, -1, 'EFG 1']],
[],
[],
[['D B 544', 2, 'D B 544', 1, -1, 'EFG 11'], ['D B 152', 3, 'D B 152', 2, -1, 'EFG 11'], ['D B 682', 3, 'D B 682', 2, -1, 'EFG 11']],
]

import csv
# Write to File
with open('Output.csv', 'w') as csv_file:
    writer = csv.writer(csv_file)
    for _list in data:
        for row_data in _list:
            writer.writerow(row_data)

Qutput:

A B 10,2,A B 10,3,1,AC
A B 104,3,A B 104,2,-1,AC
D B 126,3,D B 126,2,-1,EFG 1
D B 15,3,D B 15,2,-1,EFG 1
D B 544,2,D B 544,1,-1,EFG 11
D B 152,3,D B 152,2,-1,EFG 11
D B 682,3,D B 682,2,-1,EFG 11

测试 Python: 3.4.2 - openpyxl: 2.4.1

Answer 3

看起来您可以将数据很好地放入 Excel 文件中。那么为什么不使用你使用类似的东西：

col1 = [cell.value for cell in ws['A']]

或

ws.iter_cols(min_col=x, max_col=y)

如果这不是您想要的，请重新表述问题以指出问题所在。

将列表中的数据排序为 xlsx 文件的列

Sort data in a list to columns for xlsx files

python

list

python-3.x

pandas

openpyxl