在子函数中输入大量元素并在 main() 中相乘

Question

我必须在子函数中输入大量的元素，在main()函数中输入小于最大元素的多元素。
为了输入元素，我写了这段代码：

#include <stdio.h>
#define K 70

int input_ar (int* x){
    int i;
    printf("Inputing elements of massive \n");
    for(i=0;i<K;i++){
        printf("Please, enter element %d:", i);
        scanf("%d", &x[i]);
    }
}

相乘：

int main(){
    int x, i, mult=1;
    int max=input_ar(0);
    for(i=0;i<K;i++){
        if(input_ar(i)>max){
            max=input_ar(i);
        }
        if(input_ar(i)<max){
            mult*=input_ar(i);
        }

    }
    printf("\n Sum of elements = %d ", mult);
}

但我收到错误：

[Error] void value not ignored as it ought to be
[Error] invalid conversion from 'int' to 'int*' [-fpermissive]

如何消除这些错误？

Answer 1

您的函数 input_ar 有一个 int* 类型的参数。您将 int 值传递给函数。这就是编译器所抱怨的。您还应该 return 来自 input_ar 和 main 的 int，尽管如果您使用 C99 或 C11 进行编译，它可能会在 main 的情况下自动提供在该标准中看到：

5.1.2.2.3 Program termination

If the return type of the main function is a type compatible with int, a return from the initial call to the main function is equivalent to calling the exit function with the value returned by the main function as its argument; ¹¹ reaching the } that terminates the main function returns a value of 0. If the return type is not compatible with int, the termination status returned to the host environment is unspecified.

Answer 2

主要功能必须return。在 main.

末尾添加 return 语句

return 0;

你定义的函数将参数作为整数指针*x，但你传递的是值i。就这样吧

input_ar(&i);

在所有地方。然后你放置这条线，

mult*=input_ar(i);

但是您正在return从那个函数中获取任何东西。您必须从该函数 return。

Answer 3

接住！:)

#include <stdio.h>

#define N   70

int input_ar( int *a, int n )
{
    int i = 0;

    printf( "Inputing elements of massive\n" );

    for ( ; i < n; i++ )
    {
        printf( "Please, enter element %d: ", i );
        if ( scanf( "%d", &a[i] ) != 1 ) break;
    }

    return i;
}

int max_element( const int *a, int n )
{
    int max = 0;
    int i;

    for ( i = 1; i < n; i++ ) if ( a[max] < a[i] ) max = i;

    return max;
}

int main(void) 
{
    int a[N];
    int n = input_ar( a, N );
    int max = max_element( a, n );

    int count = 0;
    int long long product = 1;
    int i;

    for ( i = 0; i < n; i++ )
    {
        if ( a[i] != a[max] )
        {
            ++count;
            product *= a[i];
        }
    }

    if ( count != 0 ) 
    {
        printf( "The product of elements "
                "that are not equal to the maximum element "
                "is %lld\n", product );
    }
    else
    {
        puts( "All elements of the array are equal each other" );
    }

    return 0;
}

至于你的代码，那么它包含许多错误，从函数 input_ar 开始，returns 什么都没有，并以表示总和而不是乘积的字符串文字结尾

"\n Sum of elements = %d "

在子函数中输入大量元素并在 main() 中相乘

Inputting elements of massive in sub-function and multiplying in main()

c

int

void