SQL 在 table 值函数中使用 #table/ Temp table
SQL using #table/ Temp table inside a table valued function
我需要一个函数来获取给定日期范围内的所有周数。
我必须将它与我的存储过程分开,因为它有一个漫长的过程。
但是当我在函数中使用#tables 时,它给出了以下错误
Msg 2772, Level 16, State 1, Procedure WeekNumbersWithinRange, Line 19
Cannot access temporary tables from within a function.
这是我的功能。
CREATE FUNCTION WeekNumbersWithinRange
(
@FromDate DATETIME,
@ToDate DATETIME
)
RETURNS TABLE
AS
BEGIN
IF OBJECT_ID (N'tempdb..#WeeksofRange', N'U') IS NOT NULL
BEGIN
DROP TABLE #WeeksofRange
END
CREATE TABLE #WeeksofRange (WeekNo INT);
-- Get all week numbers for the given delivery date range
IF OBJECT_ID (N'tempdb..#Calendar', N'U') IS NOT NULL
BEGIN
DROP TABLE #Calendar
END
CREATE TABLE #Calendar
(
CalendarDate DATE PRIMARY KEY,
IsWeekend BIT,
YearNo SMALLINT,
QuarterNo TINYINT,
MonthNo TINYINT,
DayOfYearNo SMALLINT,
DayNo TINYINT,
WeekNo TINYINT,
WeekDayNo TINYINT
)
DECLARE @beginDate DATE, @endDate DATE
SELECT
@beginDate = @FromDate, @endDate = @ToDate
WHILE @beginDate <= @endDate
BEGIN
INSERT INTO #Calendar (CalendarDate, IsWeekend, YearNo, QuarterNo, MonthNo, DayOfYearNo, DayNo, WeekNo, WeekDayNo)
SELECT
@beginDate As CalendarDate,
(CASE WHEN DATEPART(Weekday, @beginDate) IN (7, 1)
THEN 1 ELSE 0
END) AS IsWeekend,
DATEPART(Year, @beginDate) AS YearNo,
DATEPART(QUARTER, @beginDate) AS QuarterNo,
DATEPART(MONTH, @beginDate) AS MonthNo,
DATEPART(DayOfYear, @beginDate) AS DayOfYearNo,
DATEPART(Day, @beginDate) AS DayNo,
DATEPART(Week, @beginDate) AS WeekNo,
DATEPART(WEEKDAY, @beginDate) AS WeekDayNo
--,(Case When @beginDate < '02/03/2011' Then 0 Else DATEPART(Week, @beginDate) - 5 End) As mySpecificWeekNo
SET @beginDate = DATEADD(Day, 1, @beginDate)
END
INSERT INTO #WeeksofRange
SELECT DISTINCT WeekNo
FROM #Calendar;
-- End of Select all week numbers in the range
SELECT * FROM #WeeksofRange
GO
还有其他方法吗?或者我需要在我的存储过程中编写这个逻辑吗?
您不能在 UDF 中使用临时 table,因为
the object can't be created inside UDF.
不要使用 Temp table,而是使用 table 变量,这应该可以解决您的问题
CREATE FUNCTION WeekNumbersWithinRange
(
@FromDate DATETIME,
@ToDate DATETIME
)
RETURNS TABLE
AS
BEGIN
DECLARE @WeeksofRange TABLE
(
WeekNo INT
)
-- Get all week numbers for the given delivery date range
declare @Calendar table
(CalendarDate Date Primary key, IsWeekend Bit, YearNo SmallInt, QuarterNo TinyInt, MonthNo TinyInt, DayOfYearNo SmallInt, DayNo TinyInt, WeekNo TinyInt, WeekDayNo TinyInt )
Declare @beginDate Date, @endDate Date
Select @beginDate = @FromDate , @endDate = @ToDate
While @beginDate <= @endDate
Begin
Insert Into @Calendar (CalendarDate, IsWeekend, YearNo, QuarterNo, MonthNo, DayOfYearNo, DayNo, WeekNo, WeekDayNo)
Select
@beginDate As CalendarDate
,(Case When DATEPART(Weekday, @beginDate) In (7, 1) Then 1 Else 0 End) As IsWeekend
,DATEPART(Year, @beginDate) As YearNo
,DATEPART(QUARTER, @beginDate) As QuarterNo
,DATEPART(MONTH, @beginDate) As MonthNo
,DATEPART(DayOfYear, @beginDate) As DayOfYearNo
,DATEPART(Day, @beginDate) As DayNo
,DATEPART(Week, @beginDate) As WeekNo
,DATEPART(WEEKDAY, @beginDate) As WeekDayNo
--,(Case When @beginDate < '02/03/2011' Then 0 Else DATEPART(Week, @beginDate) - 5 End) As mySpecificWeekNo
Set @beginDate = DateAdd(Day, 1, @beginDate)
End
INSERT INTO @calendar
SELECT DISTINCT WeekNo FROM @Calendar;
-- End of Select all week numbers in the range
SELECT * FROM @WeeksofRange
GO
我通常会选择使 Calendar
table 永久化并填充它,比如说,一个世纪的行。然后查询就可以了。
但是,如果您拥有此功能,您可以编写它以使用 CTE 并避免任何显式 state/iteration 管理:
CREATE FUNCTION WeekNumbersWithinRange
(
@FromDate DATETIME,
@ToDate DATETIME
)
RETURNS TABLE
AS
return (With Weeks as (
select DATEPART(week,@FromDate) as Week,@FromDate as dt
union all
select DATEPART(week,ndt),ndt
from Weeks
cross apply (select DATEADD(day,7,dt) as ndt) t
where
ndt < @ToDate
)
select Week from Weeks
union
select DATEPART(week,@ToDate)
)
我做了一个简化假设,即周数仅每 7 天更改一次,因此我们不需要在 CTE 中为每一天生成一行。另外,我使用最后的 UNION
来确保包括最后一周。它 可以 被跳过,因为我以 7 天为增量工作,所以我们可以将我们的值从前一周直接跳到大于 @ToDate
.[=15= 的值]
根据您使用的范围,您可能必须将 MAXRECURSION
选项应用到查询以允许 CTE 充分工作。
我需要一个函数来获取给定日期范围内的所有周数。 我必须将它与我的存储过程分开,因为它有一个漫长的过程。
但是当我在函数中使用#tables 时,它给出了以下错误
Msg 2772, Level 16, State 1, Procedure WeekNumbersWithinRange, Line 19
Cannot access temporary tables from within a function.
这是我的功能。
CREATE FUNCTION WeekNumbersWithinRange
(
@FromDate DATETIME,
@ToDate DATETIME
)
RETURNS TABLE
AS
BEGIN
IF OBJECT_ID (N'tempdb..#WeeksofRange', N'U') IS NOT NULL
BEGIN
DROP TABLE #WeeksofRange
END
CREATE TABLE #WeeksofRange (WeekNo INT);
-- Get all week numbers for the given delivery date range
IF OBJECT_ID (N'tempdb..#Calendar', N'U') IS NOT NULL
BEGIN
DROP TABLE #Calendar
END
CREATE TABLE #Calendar
(
CalendarDate DATE PRIMARY KEY,
IsWeekend BIT,
YearNo SMALLINT,
QuarterNo TINYINT,
MonthNo TINYINT,
DayOfYearNo SMALLINT,
DayNo TINYINT,
WeekNo TINYINT,
WeekDayNo TINYINT
)
DECLARE @beginDate DATE, @endDate DATE
SELECT
@beginDate = @FromDate, @endDate = @ToDate
WHILE @beginDate <= @endDate
BEGIN
INSERT INTO #Calendar (CalendarDate, IsWeekend, YearNo, QuarterNo, MonthNo, DayOfYearNo, DayNo, WeekNo, WeekDayNo)
SELECT
@beginDate As CalendarDate,
(CASE WHEN DATEPART(Weekday, @beginDate) IN (7, 1)
THEN 1 ELSE 0
END) AS IsWeekend,
DATEPART(Year, @beginDate) AS YearNo,
DATEPART(QUARTER, @beginDate) AS QuarterNo,
DATEPART(MONTH, @beginDate) AS MonthNo,
DATEPART(DayOfYear, @beginDate) AS DayOfYearNo,
DATEPART(Day, @beginDate) AS DayNo,
DATEPART(Week, @beginDate) AS WeekNo,
DATEPART(WEEKDAY, @beginDate) AS WeekDayNo
--,(Case When @beginDate < '02/03/2011' Then 0 Else DATEPART(Week, @beginDate) - 5 End) As mySpecificWeekNo
SET @beginDate = DATEADD(Day, 1, @beginDate)
END
INSERT INTO #WeeksofRange
SELECT DISTINCT WeekNo
FROM #Calendar;
-- End of Select all week numbers in the range
SELECT * FROM #WeeksofRange
GO
还有其他方法吗?或者我需要在我的存储过程中编写这个逻辑吗?
您不能在 UDF 中使用临时 table,因为
the object can't be created inside UDF.
不要使用 Temp table,而是使用 table 变量,这应该可以解决您的问题
CREATE FUNCTION WeekNumbersWithinRange
(
@FromDate DATETIME,
@ToDate DATETIME
)
RETURNS TABLE
AS
BEGIN
DECLARE @WeeksofRange TABLE
(
WeekNo INT
)
-- Get all week numbers for the given delivery date range
declare @Calendar table
(CalendarDate Date Primary key, IsWeekend Bit, YearNo SmallInt, QuarterNo TinyInt, MonthNo TinyInt, DayOfYearNo SmallInt, DayNo TinyInt, WeekNo TinyInt, WeekDayNo TinyInt )
Declare @beginDate Date, @endDate Date
Select @beginDate = @FromDate , @endDate = @ToDate
While @beginDate <= @endDate
Begin
Insert Into @Calendar (CalendarDate, IsWeekend, YearNo, QuarterNo, MonthNo, DayOfYearNo, DayNo, WeekNo, WeekDayNo)
Select
@beginDate As CalendarDate
,(Case When DATEPART(Weekday, @beginDate) In (7, 1) Then 1 Else 0 End) As IsWeekend
,DATEPART(Year, @beginDate) As YearNo
,DATEPART(QUARTER, @beginDate) As QuarterNo
,DATEPART(MONTH, @beginDate) As MonthNo
,DATEPART(DayOfYear, @beginDate) As DayOfYearNo
,DATEPART(Day, @beginDate) As DayNo
,DATEPART(Week, @beginDate) As WeekNo
,DATEPART(WEEKDAY, @beginDate) As WeekDayNo
--,(Case When @beginDate < '02/03/2011' Then 0 Else DATEPART(Week, @beginDate) - 5 End) As mySpecificWeekNo
Set @beginDate = DateAdd(Day, 1, @beginDate)
End
INSERT INTO @calendar
SELECT DISTINCT WeekNo FROM @Calendar;
-- End of Select all week numbers in the range
SELECT * FROM @WeeksofRange
GO
我通常会选择使 Calendar
table 永久化并填充它,比如说,一个世纪的行。然后查询就可以了。
但是,如果您拥有此功能,您可以编写它以使用 CTE 并避免任何显式 state/iteration 管理:
CREATE FUNCTION WeekNumbersWithinRange
(
@FromDate DATETIME,
@ToDate DATETIME
)
RETURNS TABLE
AS
return (With Weeks as (
select DATEPART(week,@FromDate) as Week,@FromDate as dt
union all
select DATEPART(week,ndt),ndt
from Weeks
cross apply (select DATEADD(day,7,dt) as ndt) t
where
ndt < @ToDate
)
select Week from Weeks
union
select DATEPART(week,@ToDate)
)
我做了一个简化假设,即周数仅每 7 天更改一次,因此我们不需要在 CTE 中为每一天生成一行。另外,我使用最后的 UNION
来确保包括最后一周。它 可以 被跳过,因为我以 7 天为增量工作,所以我们可以将我们的值从前一周直接跳到大于 @ToDate
.[=15= 的值]
根据您使用的范围,您可能必须将 MAXRECURSION
选项应用到查询以允许 CTE 充分工作。