弹出菜单项单击侦听器功能不起作用

Question

我有一个弹出菜单，我正在为菜单中的项目执行操作；然而，当按下菜单 "notification" 中的第二项时，没有任何反应。第一项有效 "change icon" 但第二项无效。我怀疑函数内部的 evenlistener 有问题。如果有人可以指出我这样做的正确方法。我查看了 android 开发文档，他们的实现有点不同。主要 activity

package org.pctechtips.menulistview;

import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.ContextMenu;
import android.view.Menu;
import android.view.MenuInflater;
import android.view.MenuItem;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.PopupMenu;
import android.widget.Toast;

import java.util.ArrayList;

public class MainActivity extends AppCompatActivity {
    ArrayList hosts;
    String ipAdd = "192.168.10.";
    ListView list;
    ArrayAdapter<String> adapter;
    PopupMenu popup;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        hosts = new ArrayList<String>();
        for(int i = 0; i < 255; i++) {
            hosts.add(ipAdd+i);
        }

        list = (ListView) findViewById(R.id.list);
        adapter = new ArrayAdapter<String>(this, R.layout.list_item, R.id.ip_address, hosts);
        list.setAdapter(adapter);
        //registering the menu with the listview
//        registerForContextMenu(list);

    }

    /* code for popup menu in listview */
    public void showPopupMenu(View v) {
        popup = new PopupMenu(this, v);
        MenuInflater inflater = popup.getMenuInflater();
        inflater.inflate(R.menu.list_menu, popup.getMenu());

        /* handling event listeners*/
        popup.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {
            @Override
            public boolean onMenuItemClick(MenuItem menuItem) {
                switch(menuItem.getItemId()) {
                    case R.id.change_icon:
                        Toast.makeText(MainActivity.this, menuItem.getTitle(), Toast.LENGTH_SHORT).show();
                        return true;
                    case R.id.notifications:
                        Toast.makeText(MainActivity.this, menuItem.getTitle(), Toast.LENGTH_SHORT).show();
                        return true;
                    default:
                        return MainActivity.super.onOptionsItemSelected(menuItem);
                }
            }
        });
        popup.show();
    }

}

弹出菜单xml文件

 <!-- listview menu for host scan options eg:
         change hostname, icon, notification etc -->
<menu xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto">

    <!-- Settings, should always be in the overflow -->
    <item android:id="@+id/change_icon"
        android:title="change icon"
        app:showAsAction="always"/>


    <itme android:id="@+id/notifications"
        android:title="notifications"
        app:showAsAction="always"/>

    <item android:id="@+id/set_hostname"
        android:title="set notification"
        app:showAsAction="always"/>

</menu>

Answer 1

您的菜单文件中有 item 拼写错误的通知。

<itme android:id="@+id/notifications"
    android:title="notifications"
    app:showAsAction="always"/>

会不会是这个问题？

刚刚测试过，这似乎是问题所在。更正拼写，菜单应该可以正常工作。

弹出菜单项单击侦听器功能不起作用

popup menu items click listener function not working

android

xml

popup

android-menu