从文件中读取并将它们解析为不同的数组

Question

我将读取文件内容作为我程序的输入。

我将它存储到一个字符串中并将其拆分为 2 个字符串。

File file = new File("question.txt");
PrintWriter pw = new PrintWriter(file);
pw.write("81 : (1,53.38,) (2,88.62,) (3,78.48,) (4,72.30,) (5,30.18,) (6,46.34,)");
pw.close();
BufferedReader br = new BufferedReader(new FileReader(file));
String line = br.readLine();
Map<Integer, Object> map = new HashMap<Integer, Object>();
int i = 0;
Demo d = new Demo();
String[] part = line.split(":");
String part1 = part[0].trim();
String part2 = part[1].trim();

输入： 81 : (1,53.38,) (2,88.62,) (3,78.48,) (4,72.30,) (5,30.18,) (6,46.34,)

输出：

totalWeight = 81;
index[] = {1,2,3,4,5,6}; 
weight[] = {53.38,88.62,78.48,72.30,30.18,46.34};  
value[] = {45,98,3,76,9,48};

第二个字符串包含括号内的 3 个值。第一个数字是 "Index"，第二个数字是 "Weight"，第三个数字是 "Value".
我如何将它拆分并存储到 3 个不同的数组中？

我知道一种方法是将其解析为 class 的对象，该对象具有 3 个数组并为它们赋值。
但是有没有更好的方法呢？

Answer 1

String[] part2 = part[1].replace("(", "").trim().split(")");
List<String> indices = new ArrayList<String>();
List<String> weights= new ArrayList<String>();
List<String> values = new ArrayList<String>();

for (String s : part2)
{
   String item = s.split(",");
   indices.add(item[0]);
   weights.add(item[1]);
   values.add(item[2]);
}

// to get them as arrays
String[] allWeightsArray = weights.toArray(new String[]); ...

Answer 2

使用此代码解析此格式的字符串：

String[] structured = part2.replaceAll("[()]", "").split(" ");

List<String> indexes = new ArrayList<>();
List<String> weights = new ArrayList<>();
List<String> values = new ArrayList<>();

for (String elem : structured) {
    String[] parsed = elem.split(",");
    indexes.add(parsed[0]);
    weights.add(parsed[1]);
    values.add(parsed[2]);
}

Answer 3

使用split方法将字符串拆分为[\(?+\)]+\s+

String x = part[1].trim(); 
String[] items = x.split("[\(?+\)]+\s+");
List<String> indexs = new ArrayList<>();
List<String> wights = new ArrayList<>();
List<String> values = new ArrayList<>();
for(String item : items)
{
    item = item.replace("(" , "").replace(")" , "").trim();
    String[] partItems = item.split(",");
    indexs.add(partItems[0]);
    wights.add(partItems[1]);
    values.add(partItems[2]);
}

System.out.println(Arrays.toString(indexs.toArray()));
System.out.println(Arrays.toString(wights.toArray()));
System.out.println(Arrays.toString(values.toArray()));

输出

[1, 2, 3, 4, 5, 6]
[53.38, 88.62, 78.48, 72.30, 30.18, 46.34]
[, , , , , ]

Answer 4

您可以使用这样的模式解决您的问题：

String str = "81 : (1,53.38,) (2,88.62,) (3,78.48,) "
    + "(4,72.30,) (5,30.18,) (6,46.34,)";

String regex = "\((\d+),(\d+\.\d+),([^\d](\d+))\)";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(str);
double totalWeight = Double.parseDouble(str.replaceAll("^(\d+).*", ""));
List<Integer> indexes = new ArrayList<>();
List<Double> weights = new ArrayList<>();
List<Integer> valuess = new ArrayList<>();

while (matcher.find()) {  
    indexes.add(Integer.parseInt(matcher.group(1)));
    weights.add(Double.parseDouble(matcher.group(2)));
    valuess.add(Integer.parseInt(matcher.group(4)));
}

System.out.println(totalWeight);// 81.0
System.out.println(indexes);    // [1, 2, 3, 4, 5, 6]
System.out.println(weights);    // [53.38, 88.62, 78.48, 72.3, 30.18, 46.34]
System.out.println(valuess);    // [45, 98, 3, 76, 9, 48]

总重量是输入中的第一个数字，您只需使用 replaceAll 即可获得它，然后解析输入 Double.parseDouble(str.replaceAll("^(\d+).*", ""));
要获取其余信息，您可以使用此正则表达式 \((\d+),(\d+\.\d+),([^\d](\d+))\) (regex demo)，它可以匹配两个 () 之间的三个不同数字，在您的情况下，您有很多结果你可以使用模式。

从文件中读取并将它们解析为不同的数组

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