获取从四月的第一个星期一到下一个四月的第一个星期一开始计算周数的周数 PHP

Question

我正在努力实现以下目标：

出于报告目的，我们的周数从每年 4 月的第一个星期一开始。

我正在使用以下格式使用 PHP 创建日历：

M T W T F S S

在该月每一行的末尾，我想显示周数，从 1 开始，四月的第一个星期一将是第一周，一直到四月的下一个第一个星期一（明年）它又从哪里开始。

我在逻辑上苦苦挣扎 - 谁能提出解决方案？

谢谢

编辑看下面我的代码，基本上我想做的不是从 1 月 1 日开始的周数，而是从 4 月的第一个星期一开始的：

<?php
$monthNames = Array("January", "February", "March", "April", "May",     "June", "July", 
"August", "September", "October", "November", "December");
?>

<?php
if (!isset($_REQUEST["month"])) $_REQUEST["month"] = date("n");
if (!isset($_REQUEST["year"])) $_REQUEST["year"] = date("Y");
?>

<?php
$cMonth = $_REQUEST["month"];
$cYear = $_REQUEST["year"];

$prev_year = $cYear;
$next_year = $cYear;
$prev_month = $cMonth-1;
$next_month = $cMonth+1;

if ($prev_month == 0 ) {
    $prev_month = 12;
    $prev_year = $cYear - 1;
}
if ($next_month == 13 ) {
    $next_month = 1;
    $next_year = $cYear + 1;
}
?>

<table width="250">
<tr align="center">
<td bgcolor="#999999" style="color:#FFFFFF">
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td width="50%" align="left">  <a href="<?php echo $_SERVER["PHP_SELF"] . "?month=". $prev_month . "&year=" . $prev_year; ?>" style="color:#FFFFFF">Previous</a></td>
<td width="50%" align="right"><a href="<?php echo $_SERVER["PHP_SELF"] . "?month=". $next_month . "&year=" . $next_year; ?>" style="color:#FFFFFF">Next</a>  </td>
</tr>
</table>
</td>
</tr>
<tr>
<td align="center">
<table width="100%" border="0" cellpadding="2" cellspacing="2">
<tr align="center">
<td colspan="8" bgcolor="#999999" style="color:#FFFFFF"><strong><?php echo $monthNames[$cMonth-1].' '.$cYear; ?></strong></td>
</tr>
<tr>
<td align="center" bgcolor="#999999" style="color:#FFFFFF"><strong>M</strong></td>
<td align="center" bgcolor="#999999" style="color:#FFFFFF"><strong>T</strong></td>
<td align="center" bgcolor="#999999" style="color:#FFFFFF"><strong>W</strong></td>
<td align="center" bgcolor="#999999" style="color:#FFFFFF"><strong>T</strong></td>
<td align="center" bgcolor="#999999" style="color:#FFFFFF"><strong>F</strong></td>
<td align="center" bgcolor="#999999" style="color:#FFFFFF"><strong>S</strong></td>
<td align="center" bgcolor="#999999" style="color:#FFFFFF"><strong>S</strong></td>
<td align="center" bgcolor="#999999" style="color:#FFFFFF"><strong>Week No</strong></td>
</tr>


<?php 
$timestamp = mktime(0,0,0,$cMonth,1,$cYear);
$maxday = date("t",$timestamp);
$thismonth = getdate ($timestamp);
//$startday = $thismonth['wday'];
$startday = $thismonth['wday']-1;

$firstDateMonth = 0;

function roundToNearestW($int, $i) {
    return ceil($int / $i) * $i;
}

if ($startday == -1)
{
    $startday = 6;
}
$complete_cells = roundToNearestW($maxday+$startday,7);
for ($i=0; $i<($complete_cells); $i++) {
    if(($i % 7) == 0 )
    {
        echo "<tr>
        ";
    }
    if($i < $startday || $i >= $maxday+$startday)
    {
        echo "<td></td>
        ";
    }
    else
    {
        if(($i - $startday + 1) > $firstDateMonth)
        {
            $firstDateMonth = ($i - $startday + 1);
        }
        echo "<td align='center' valign='middle' height='20px'>". ($i - $startday + 1) . "</td>
        ";
    }
    if(($i % 7) == 6 )
    {
        $weekDate = $cYear."-".$cMonth."-".$firstDateMonth;
        $Caldate = new DateTime($weekDate);
        $week = $Caldate->format("W");
        echo "<td align='center' valign='middle' height='20px'>WK ".$week."</td>
        ";
    }
    if(($i % 7) == 6 )
    {
        echo "</tr>";
        //firstDateMonth = 0;
    }

}
?>



</table>
</td>
</tr>
</table>

以上日历的部分功劳（我自己稍微调整了代码）到：https://www.phpjabbers.com/how-to-make-a-php-calendar-php26-4.html

Answer 1

希望以下逻辑能满足您的需求。

<?php

$begin    = new DateTime(date('Y-m-d', strtotime('first Monday of April this year')));
$end      = new DateTime(date('Y-m-d', strtotime('last Monday of March next year')));
$interval = DateInterval::createFromDateString('1 week');

$weekNumberOfFirstMondayInApril = $begin->format('W');

foreach (new DatePeriod($begin, $interval, $end) as $dt) {
    $phpWeekNum = $dt->format('W');

    $isFirstQuarter = ($phpWeekNum < $weekNumberOfFirstMondayInApril);

    $businessWeekNum = $isFirstQuarter
        ? ($phpWeekNum + (52 - $weekNumberOfFirstMondayInApril)) 
        : ($phpWeekNum - $weekNumberOfFirstMondayInApril) ;

    echo 'Date: ' . $dt->format('l, Y-m-d') . PHP_EOL;
    echo 'PHP week number: ' . $phpWeekNum . PHP_EOL;
    echo 'Business week number: ' . ($businessWeekNum + 1) . PHP_EOL;
    echo PHP_EOL;
}

输出结果如下：

Date: Monday, 2017-04-03
PHP week number: 14
Business week number: 1

    <snip>

Date: Monday, 2017-12-25
PHP week number: 52
Business week number: 39

Date: Monday, 2018-01-01
PHP week number: 01
Business week number: 40

    <snip>

Date: Monday, 2018-03-26
PHP week number: 13
Business week number: 52

Answer 2

这对我来说似乎不那么复杂，循环内的处理更少。 DateInterval('P7D') 只是表示将间隔设置为 7 天（1 周）——这可能是唯一因为语法而有点混乱的部分。 DatePeriod() 为您完成所有艰苦的工作。

代码 (Demo)

$year=2018;  // $_GET['year'];
$next=$year+1;
$start=new DateTime(date('Y-m-d', strtotime("first Monday of April $year")));
$stop=new DateTime(date('Y-m-d', strtotime("first Monday of April $next")));
// there is a known behavior of DatePeriod to stop before $stop (...not contain it)
// See http://au2.php.net/manual/en/class.dateperiod.php for explanations & workarounds
$range=new DatePeriod($start,new DateInterval('P7D'),$stop);
echo "<table>";
    echo "<tr>";
        echo "<th colspan=\"8\">Financial Calendar $year-$next</th>";
    echo "</tr>";
    echo "<tr>";
        echo "<th>M</th><th>T</th><th>W</th><th>T</th><th>F</th><th>S</th><th>S</th><th>#</th>";
    echo "</tr>";
    foreach ($range as $i=>$date) {
        echo "<tr>";
            echo "<td></td><td></td><td></td><td></td><td></td><td></td><td></td><td>",++$i,"(",$date->format("Y-m-d"),")</td>";
        echo "</tr>";
    }
echo "</table>";

输出（未渲染）：

<table>
    <tr>
        <th colspan="8">Financial Calendar 2018-2019</th>
    </tr>
    <tr>
        <th>M</th><th>T</th><th>W</th><th>T</th><th>F</th><th>S</th><th>S</th><th>#</th>
    </tr>
    <tr>
        <td></td><td></td><td></td><td></td><td></td><td></td><td></td><td>1(2018-04-02)</td>
    </tr>
    <tr>
        <td></td><td></td><td></td><td></td><td></td><td></td><td></td><td>2(2018-04-09)</td>
    </tr>
    <tr>
        <td></td><td></td><td></td><td></td><td></td><td></td><td></td><td>3(2018-04-16)</td>
    </tr>
    ...
    <tr>
        <td></td><td></td><td></td><td></td><td></td><td></td><td></td><td>50(2019-03-11)</td>
    </tr>
    <tr>
        <td></td><td></td><td></td><td></td><td></td><td></td><td></td><td>51(2019-03-18)</td>
    </tr>
    <tr>
        <td></td><td></td><td></td><td></td><td></td><td></td><td></td><td>52(2019-03-25)</td>
    </tr>
</table>

现在，我不想剥夺您为自己开发这段代码的机会，所以我就到此为止。这应该给你一个立足点来完成这个项目，达到你想要的规格。

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