如何将 tibbles 与常见但 non-identical 列组合？

Question

我有两个小标题，每个小标题最多有 4 列。每个列名要么对两者通用，要么从一个或另一个中丢失。我需要将它们组合成两行的小标题，并在缺少它们的列中组合 NA 。我需要一般地执行此操作，因此它可以处理或多或少缺少的列。这是从两个示例网页生成 tibbles 的代码；

library(tidyverse)
library(htmltab)

read_results <- function(filename) {
  doc <- read_file(filename)
  df <- as_tibble(htmltab(doc=doc, which="//table[@id='results']"))
  colnames(df) <- c("pos", "name", "time", "age_cat", "age_grade", "gender", "gender_pos", "note", "total_runs")
  tib = t(as_tibble(df) %>% group_by(substr(note,1,12)) %>% summarise(number=n()))

  colnames(tib) <- as.character(unlist(tib[1,]))
  tib = tib[-1,]
  r <- t(tib)
  return (r);
}

# saved from http://www.parkrun.org.uk/henleyonthames/results/weeklyresults/?runSeqNumber=2
r2 = read_results("results _ henleyonthames parkrun_2.html")
# saved from http://www.parkrun.org.uk/henleyonthames/results/weeklyresults/?runSeqNumber=4
r4 = read_results("results _ henleyonthames parkrun_4.html")

现在 t2 和 t4 包含

> r2
     First Timer! New PB! PB stays at  <NA>
[1,] "58"         "11"    " 3"         " 4"
> r4
     First Timer! New PB! PB stays at 
[1,] "62"         "16"    "11"

我想将 t_all 构建为

     First Timer! New PB! PB stays at  <NA>
     58           11        3           4
     62           16       11           0

Answer 1

您的问题是 r2 的其中一列的名称为 NA。因此，大多数根据列名将类似矩阵的对象配对的函数都会失败。要解决它，请将此行添加到您的函数中：names(tib)[is.na(names(tib))] <- "Blank"

library(tidyverse)
library(htmltab)

read_results <- function(filename) {
  doc <- read_file(filename)
  df <- as_tibble(htmltab(doc=doc, which="//table[@id='results']"))
  colnames(df) <- c("pos", "name", "time", "age_cat", "age_grade", "gender", "gender_pos", "note", "total_runs")
  tib = t(as_tibble(df) %>% group_by(substr(note,1,12)) %>% summarise(number=n()))

  colnames(tib) <- as.character(unlist(tib[1,]))
  tib = tib[-1,]
  names(tib)[is.na(names(tib))] <- "Blank"  ## New Line
  r <- t(tib)
  return (r);
}

# saved from http://www.parkrun.org.uk/henleyonthames/results/weeklyresults/?runSeqNumber=2
r2 = read_results("results _ henleyonthames parkrun_2.html")
# saved from http://www.parkrun.org.uk/henleyonthames/results/weeklyresults/?runSeqNumber=4
r4 = read_results("results _ henleyonthames parkrun_4.html")

dplyr::bind_rows(as_data_frame(r2),as_data_frame(r4))

# A tibble: 2 × 4
  `First Timer!` `New PB!` `PB stays at ` Blank
           <chr>     <chr>          <chr> <chr>
1             58        11              3     4
2             62        16             11  <NA>

如何将 tibbles 与常见但 non-identical 列组合？

How to combine tibbles with common but non-identical columns?

r

tibble