如何根据指针地址获取指针内容

Question

我用ctypes调用一个dll来读取存储的内容area.But它returns一个unsigned char指针，我想得到pointer.How的内容吗我做吗？

from ctypes import *

c = WinDLL("FT_ET99_API.dll")
hwnd = c_void_p()
c.et_OpenToken(byref(hwnd), c_char_p('53E00FD8'), c_int(1))
c.et_Verify(hwnd, c_int(0), c_char_p('35316D69696C616E'))
f = c.et_Read
f.argtypes = c_void_p, c_int, c_int, POINTER(c_char_p)
f.restype = None
txt = c_char_p()
f(hwnd, 1, 34, byref(txt))
（What should I do next?）

et_Read（ 

ET_HANDLE hHandle(in),

WORD offset(in), 

int Len(in), 

unsigned char* pucReadBuf(out) 

）

Answer 1

我尝试了另一种方法，它 succeeded.I 获取了原始缓冲区的内容。

from ctypes import *

c = WinDLL("FT_ET99_API.dll")
hwnd = c_void_p()
c.et_OpenToken(byref(hwnd), c_char_p('53E00FD8'), c_int(1))
c.et_Verify(hwnd, c_int(0), c_char_p('35316D69696C616E'))
outData = create_string_buffer(34)
c.et_Read(hwnd, 1, 34, outData)
print outData.value（my aim）

如何根据指针地址获取指针内容

How to get the pointer content based on the pointer address

c

c++

python

ctypes

pointers