为什么我的 python 代码没有运行完整

Question

谁能帮我理解为什么我非常简单的剪刀石头布代码会卡住并在第 18 行末尾退出？我单独测试了每个部分并且它可以工作，它可能不是最漂亮的代码但它似乎完成了工作，但是在它的最新迭代中它只是在第 18 行的结尾退出，退出代码 0，所以没有错误, 没有说有什么不对，它只是不执行下一行，就像那一行有一个中断或退出，但没有：

 import random

def startgame():
    print("Please choose rock - r, paper - p or scissors - s:")
    pchoice = input(str())
    if(pchoice.lower in ["r","rock"]):
        pchoice = "0"
    elif(pchoice.lower in ["s","scissors"]):
        pchoice = "1"
    elif(pchoice.lower in ["p","paper"]):
        pchoice = "2"
    cchoice = (str(random.randint(0,2)))
    if(cchoice == "0"):
        print("Computer has chosen: Rock \n")
    elif(cchoice == "1"):
        print("Computer has chosen: Scissors \n")
    elif(cchoice == "2"):
        print("Computer has chosen: Paper \n")
#runs perfect up to here, then stops without continuing
    battle = str(pchoice + cchoice)
    if(battle == "00" and "11" and "22"):
        print("Draw! \n")
        playagain()
    elif(battle == "02" and "10" and "21"):
        if(battle == "02"):
            print("You Lose! \nRock is wrapped by paper! \n")
        elif(battle == "10"):
            print("You Lose! \nScissors are blunted by rock! \n")
        elif(battle == "21"):
            print("You Lose! \nPaper is cut by scissors! \n")
            playagain()
    elif(battle == "01" and "12" and "20"):
        if(battle == "01"):
            print("You Win! \nRock blunts scissors! \n")
        elif(battle == "12"):
            print("You Win! \nScissors cut paper! \n")
        elif(battle == "20"):
            print("You Win! \nPaper wraps rock! \n")
            playagain()

def main():
    print("\nWelcome to Simon´s Rock, Paper, Scissors! \n \n")
    startgame()

def playagain():
        again = input("Would you like to play again? y/n \n \n")
        if(again == "y"):
            startgame()
        elif(again == "n"):
            print("Thank you for playing")
            exit()
        else:
            print("Please choose a valid option...")
        playagain()

main()

Answer 1

错误在这里：

if(battle == "00" and "11" and "22"):

这将在所有情况下计算为 False，但 00，您需要将其更改为：

if battle == "00" or battle == "11" or battle == "22":

以及您使用 and

的其他两个语句

您的陈述被解释如下：

True/False 1- if battle == "00" 
True       2- and "11" #<-- here it checks if the string is True which means string is not empty
True       3- and "22" is True #<-- here too

所以您的语句只有在所有语句都是 True 时才有效，因为您使用的是 and，这要求语句的所有部分都是 True。第二和第三部分总是 True 所以它检查选择是否是 "00"

你需要的是：

1- if battle == "00" True/False
2- or battle == "11" True/False
3- or battle == "22" True/False

你只需要一个部分True，因为or

Answer 2

在像这样的行中 if(battle == "00" and "11" and "22"): 使用 in 运算符 if(battle in ["00", "11", "22"]):

playagain() 未被调用，因为 none 的条件为真。

为什么我的 python 代码没有运行完整

why is my python code not running fully

python

exit

break

为什么我的 python 代码没有 运行 完整

why is my python code not running fully

python

exit

break

为什么我的 python 代码没有运行完整