将嵌套单元绘制为预定义结构：MATLAB

Question

我有一系列代表树结构的嵌套单元格。这些单元格之一及其相应结构的示例如下图所示：

我想知道在Matlab中绘制相应结构的可能方法有哪些。到目前为止，我发现 this method here 这可能是可用的最佳解决方案，但我仍在努力实现它。谢谢

Answer 1

这样就不会没有答案了...

myCellArray = {0,0,{1,0,0,{1,0},0,0},{1,0,{1,0},0},{1,1},0,0};
[myTreeArray,myTreeEvals] = getTreeArray(myCellArray);
MYtreeplot(myTreeArray,myTreeEvals)

对于第四个示例输出，您可以根据需要进行修改：

两个函数，稍微改编自 SO 答案，如下所示。

首先基于@Wolfie 的：

function [treearray, nodevals]  = getTreeArray(cellarray)
    % initialise the array construction from node 0
    [nodes, ~, nodevals] = treebuilder(cellarray, 1,0); 
    nodevals = decellify(nodevals);
    treearray = nodes-1;
    % recursive tree building function, pass it a cell array and root node
    function [out, node, nodevals] = treebuilder(cellarray, rnode,skipFirst)
        % Set up variables to be populated whilst looping
        out = []; nodevals = [];
        % Start node off at root node
        node = rnode;
        % Loop over cell array elements, either recurse or add node
        num2Loop = 1:numel(cellarray);
        % ADDED, with input to function everywhere used
        if skipFirst
            num2Loop = 2:numel(cellarray);
        end
        %End ADDED
        for ii = num2Loop
            tb = []; node = node + 1;
            if iscell(cellarray{ii})
                [tb, node] = treebuilder(cellarray{ii}, node,1);
            end
            out = [out, rnode, tb];
        end
        nodevals = [nodevals,cellarray];
    end

    function data = decellify(data)
        try
            data = cellfun(@decellify,data,'un',0);
            if any(cellfun(@iscell,data))
                data = [data{:}];
            end
        catch
            % a non-cell node, so simply return node data as-is
        end
    end
end

并基于此SO answer for treeplots：

function MYtreeplot(treearray,nodevals)
% At first we need to get the get the x and y coordinates of every node in the original tree plot and find all leaves in it
[x,y] = treelayout(treearray);
leaves = find( y == min(y) );
%ADDED
if nargin < 2
    leaveParents = find( y ~= min(y) );
    leaveChilds = leaves;
else
    leaveParents = find([nodevals{:}]==1);
    leaveChilds = find([nodevals{:}]~=1);
end
%END ADDED
num_layers = 1/min(y)-1;
chains = zeros(num_layers, length(leaves));
% Next, we reconstruct every chain in the tree plot and store it in a matrix (by doing so, we can later change the y position of the nodes)
for l=1:length(leaves)
    index = leaves(l);
    chain = [];
    chain(1) = index;
    parent_index = treearray(index);
    j = 2;
    while (parent_index ~= 0)
        chain(j) = parent_index;
        parent_index = treearray(parent_index);
        j = j+1;
    end
    chains(:,l) = padarray(flip(chain), [0, num_layers-length(chain)], 'post');
end
% Now we compute the new y-coordinates determined by the row index in the matrix and dependent on the number of layers in the tree:
y_new = zeros(size(y));
for i=1:length(treearray)
    [r,c] = find(chains==i, 1);
    y_new(i) = max(y) - (r-1)*1/(num_layers+1);
end
% We can now plot the re-positioned nodes and add the connecting lines:
figure;plot(x(leaveParents), y_new(leaveParents), '.r','MarkerSize',16);
hold on
plot(x(leaveChilds), y_new(leaveChilds), '.k','MarkerSize',16);
for c=1:size(chains, 2)
    line_x = x(chains(chains(:,c)>0, c));
    line_y = y_new(chains(chains(:,c)>0, c));
    line(line_x, line_y);
end
axis([0 1 0 1]);

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