如何select按时间段（例如，小时）统计每个用户？

Question

如何编写 Postgresql 查询以按小时查找用户计数？

Table:

date                 name
-------------------  ----
2015-01-01 23:11:11  John
2015-02-02 23:22:22  John
2015-02-02 23:00:00  Mary
2015-02-02 23:59:59  Mary
2015-03-03 00:33:33  Mary

期望的输出：

        hour         | name    | count
---------------------+---------+-------
 2015-01-01 23:00:00 | John    |     1
 2015-02-02 23:00:00 | Mary    |     2
 2015-02-02 23:00:00 | John    |     1
 2015-03-03 00:00:00 | Mary    |     1

我试过了 http://www.sqlfiddle.com/#!12/a50d4/2:

CREATE TABLE my_table (
    date TIMESTAMP WITHOUT TIME ZONE,
    name TEXT
);
INSERT INTO my_table (date, name) VALUES ('2015-01-01 23:11:11', 'John');
INSERT INTO my_table (date, name) VALUES ('2015-02-02 23:22:22', 'John');
INSERT INTO my_table (date, name) VALUES ('2015-02-02 23:00:00', 'Mary');
INSERT INTO my_table (date, name) VALUES ('2015-02-02 23:59:59', 'Mary');
INSERT INTO my_table (date, name) VALUES ('2015-03-03 00:33:33', 'Mary');

SELECT DISTINCT
       date_trunc('hour', "date") AS hour,
       name,
       count(*) OVER (PARTITION BY date_trunc('hour', "date")) AS count
FROM my_table
ORDER BY hour, count;

但它给了我：

 hour                | name | count |
---------------------|------|-------|
 2015-01-01 23:00:00 | John |     1 |
 2015-02-02 23:00:00 | Mary |     3 |
 2015-02-02 23:00:00 | John |     3 |
 2015-03-03 00:00:00 | Mary |     1 |

相似：

Select distinct users group by time range
PostgreSQL: running count of rows for a query 'by minute'

Answer 1

select
    date_trunc('hour', "date") as "hour",
    name,
    count(*) as "count"
from my_table
group by 1, 2
order by 1, 3 desc;

http://www.sqlfiddle.com/#!12/a50d4/62

Answer 2

如果您想坚持使用 window 函数，您需要将 "name" 添加到您的列表中，如下所示：

http://www.sqlfiddle.com/#!12/a50d4/51

SELECT DISTINCT
   date_trunc('hour', "date") AS "hour",
   name,
   count(name) OVER (PARTITION BY name, date_trunc('hour', "date")) AS "cnt"
FROM my_table
ORDER BY hour, cnt DESC

Answer 3

我想你正在找这个

SELECT DISTINCT
       date_trunc('hour', "date") AS hour,
       name,
       count(*) as tcount
FROM my_table
GROUP BY  hour,name
ORDER BY  hour, count(*) Desc

输出：

        hour         | name    | count
---------------------+---------+-------
 2015-01-01 23:00:00 | John    |     1
 2015-02-02 23:00:00 | Mary    |     2
 2015-02-02 23:00:00 | John    |     1
 2015-03-03 00:00:00 | Mary    |     1

SQLFIDDLE

Answer 4

这对我有用：http://www.sqlfiddle.com/#!12/a50d4/57

SELECT DISTINCT name,
                date_trunc('hour', date) as hour,
                count(*) as count
FROM my_table
GROUP BY name, hour
ORDER BY hour, count DESC;

如何select按时间段（例如，小时）统计每个用户？

How to select count of each user by time period (e.g., hour)?

sql

postgresql

select

postgresql-9.2