自一对多关系与连接表未知列错误

Self OneToMany relation with jointable uknown column error

我有这些 BaseNewsNews 实体:

@MappedSuperclass
public class BaseNews extends Model {
    public static Model.Finder<Long, News> find = new Model.Finder<Long, News>(News.class);

    public static News getNewsById(Long newsId) {
        return find.byId(newsId);
    }

    public static List<News> getNewsList(int pageIndex, int pageSize) {
        return find.where()
                   .findPagedList(pageIndex, pageSize)
                   .getList();
    }
 }


    @Entity
    @Table(name = "news")
    public class News extends BaseNews implements Serializable {

        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        private Long id;


//    @ManyToOne
//    private News baseNews;


        @OneToMany(cascade = CascadeType.ALL)//,mappedBy = "baseNews")
        @JoinTable(name = "news_similar",
                   joinColumns = {@JoinColumn(name = "base_news_id")},
                   inverseJoinColumns = {@JoinColumn(name = "similar_news_id")}
        )
        private List<News> similarNews;

       //getters, setters...
    }

在单向和双向情况下

select t0.id c0, t0.base_news_id c1 from news t0

给出错误 未知列 base_news_id

我是不是做错了?

我应该创建新的 Entity NewsSimilar 而不是使用 jointable 吗?

实际上我正在反转现有的 table。

create table news_similar
(
    id int auto_increment primary key,
    base_news_id int not null,
    similar_news_id int not null,
    constraint news_similar_ibfk_1  foreign key (base_news_id) references news (id) on update cascade on delete cascade,
    constraint news_similar_ibfk_2  foreign key (similar_news_id) references news (id) on update cascade on delete cascade
)

编辑:news_id 是其他领域完全不相关的问题,无论如何都解决了。

原来我是多对多关系,所以解决方案是这样的

@Entity
@Table(name = "news")
public class News extends BaseNews implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;


    @ManyToMany(cascade = CascadeType.ALL)
    @JoinTable(name = "news_similar",
               joinColumns = {@JoinColumn(name = "base_news_id")},
               inverseJoinColumns = {@JoinColumn(name = "similar_news_id")}
    )
    private List<News> similarNews;

   //getters, setters...
}

在阅读这篇文章时得到了这个解决方案:

https://www.thoughts-on-java.org/ultimate-guide-association-mappings-jpa-hibernate/