Symfony - Sonata Abstract Admin 和 getDoctrine

Symfony - Sonata Abstract Admin and getDoctrine

我想使用 prePersist() 挂钩将获取的对象设置为准备持久化的对象。但我不知道如何将教义与 Sonata Admin Bundle 一起使用。

这是我的代码:

    namespace ShareBundle\Admin;

use Sonata\AdminBundle\Admin\AbstractAdmin;
use Sonata\AdminBundle\Datagrid\ListMapper;
use Sonata\AdminBundle\Datagrid\DatagridMapper;
use Sonata\AdminBundle\Form\FormMapper;



class UserShareAdmin extends AbstractAdmin
{
    protected function configureFormFields(FormMapper $formMapper)
    {
        $formMapper->add('quantity', 'text')
            ->add('user', 'sonata_type_model_list');
    }

    protected function configureDatagridFilters(DatagridMapper $datagridMapper)
    {
        $datagridMapper->add('quantity');
    }

    protected function configureListFields(ListMapper $listMapper)
    {
        $listMapper->addIdentifier('quantity')->addIdentifier('user')->addIdentifier('date');
    }

    public function prePersist($object)
    {
        $shareManager = $this->getDoctrine()->getManager()->getRepository('ShareBundle:Share');
        $value = $shareManager->findOneBy(array(), array('date' => 'DESC'));
        $object->setShare($value);
    }
}

有人知道怎么做吗?

谢谢!

好的伙计们,我已经弄明白了!

我必须在我的服务参数中指定 orm 默认实体管理器

#app/config/services.yml

arguments: [~, ShareBundle\Entity\UserShare, ~, @doctrine.orm.default_entity_manager]

而且我不得不在我的管理员中扩展构造函数 class。

 public function __construct($code, $class, $baseControllerName, $em)
{
    parent::__construct($code, $class, $baseControllerName);
    $this->em = $em;
}

(感谢